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Harman [31]
3 years ago
7

A chemist heats a fixed amount of gas in a sealed glass container. Which law is the chemist most likely investigating?

Chemistry
2 answers:
PilotLPTM [1.2K]3 years ago
8 0

The law which this chemist is most likely investigating heating a fixed amount of gas in a sealed glass container is: Gay Lussac’s law.

Gay Lussac's law states that when the volume of an ideal amount of gas is held (kept) constant, the pressure of the gas is directly proportional to the absolute (Kelvin) temperature of the gas.

Mathematically, Gay Lussac's law is calculated by using the formula;

PT = K\\\\\frac{P_1}{T_1} = \frac{P_2}{T_2}

<u>Where:</u>

  • P_1 is the original pressure.
  • P_2 is the final pressure.
  • T_1 is the original temperature.
  • T_2 is the final temperature.

In conclusion, the chemist is most likely investigating how changes in temperature affect the pressure of the gas by heating a fixed amount in a sealed glass container in accordance with Gay Lussac's law.

Read more: brainly.com/question/24928274

galina1969 [7]3 years ago
4 0

Gases Unit Test Honors Chemistry A

1) B. The volume increases to twice its original value.

2) A. volume and temperature directly proportional

pressure and volume inversely proportional

pressure and temperature directly proportional

3) D. Gay-Lussac’s law, by seeing how changes in temperature affect the pressure of the gas

4) B. V1P1/T1=V2P2/T2

5) A. It is a straight line with a positive slope showing that an increase in temperature results in an increase in volume.

6) D. keeping the pressure constant and increasing the temperature

7) A. When temperature is held constant and volume increases, the pressure increases.

8) D. pressure, volume, temperature, number of moles

9) A. volume

10) A. 7.10 L/mol

11) A. 0.105 mol

12) B. 27 g/mol

13) B. the temperature increasing by a factor of 2

14) brainly.com/question/24915187

15) brainly.com/question/24544023

16)brainly.com/question/24544061

17) brainly.com/question/24598785

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sammy [17]

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Sb2O3(s)+6NaOH(aq)→2Na3SbO3(aq)+3H2O(l)

The equation is already balanced.

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3 0
1 year ago
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. this result indicates
LuckyWell [14K]
When alpha particles are used to bombard gold foil, most of the alpha particles pass through undeflected. This result of the experiment indicates that most of the volume of a gold atom consists of unoccupied spaces. This was an experiment done by Ernest Rutherford which allowed him to verify the presence of the a small region positive charge in an atom which is called as the nucleus of the atom. Most of the alpha particles pass through the foil while a certain amount were deflected. Those that pass through confirmed that there is a large area that is unoccupied in an atom.
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4 years ago
The heating curve for a sample of pure ethanol shows the slope of the line for gaseous state is greater than the slope of the li
Agata [3.3K]

Answer:

a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.

Explanation:

The heating curve is a curve that represents temperature (T) in the y-axis vs. added heat (Q) in the x-axis. The slope is T/Q = 1/C, where C is the heat capacity. Then, the higher the slope, the lower the heat capacity. For a constant mass, it can also represent the specific heat capacity (c).

Heats of vaporization and fusion cannot be calculated from these sections of the heating curve.

<em>Which statement below explains that?</em>

<em>a. The specific heat capacity of the gaseous ethanol is less than the specific heat capacity of liquid ethanol.</em> YES.

<em>b. The specific heat capacity of the gaseous ethanol is greater than the specific heat capacity of liquid ethanol.</em> NO.

<em>c. The heat of vaporization of ethanol is less than the heat of fusion of ethanol.</em> NO.

<em>d. The heat of vaporization of ethanol is greater than the heat of fusion of ethanol.</em> NO.

3 0
3 years ago
Whoever answers my question correctly I'll give 50 points​
Jet001 [13]

Answer:

okii is it on your page

Explanation:

4 0
3 years ago
Read 2 more answers
PLEASE HELP!! WILL MARK BRAINLIEST
Andrew [12]

Answer:

The answer to your question is below

Explanation:

                                         Trial 1                   Trial 2

mass of Mg                      0.255 g                0.353 g

mass of MgO                   0.418 g                 0.576 g

Chemical reaction

                                2Mg(s)    +  O₂(g)     ⇒   2MgO(s)

Question 1.

Atomic mass of Mg = 24.31 x 2 = 48.62 g

Molecular mass of MgO = 2(24.31 + 16) = 80.62 g

Trial 1

                          48.62 g of Mg ----------------- 80.62 g of MgO

                          0.255 g            ----------------   x

                          x = (0.255 x 80.62)/48.62

                          x = 0.422 g of MgO

Trial 2                48.62 g of Mg ----------------- 80.62 g of MgO

                          0.353 g            ----------------   x

                          x = (0.353 x 80.62)/48.62

                          x = 0.585 g of MgO

Question 2

Trial 1          

Percent yield = 0.418/0.422 x 100 = 99%

Trial 2

Percent yield = 0.576/0.585 x 100 = 98.5%

Question 3

Average = (99 + 98.5)/2

              = 98.75%

3 0
3 years ago
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