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antiseptic1488 [7]
4 years ago
5

Planet X has the half the size of Earth and a density three times that of the Earth. Determine the acceleration due to gravity o

n Planetx Select one: 9/2 2g/3 39/2 2g 3
Physics
1 answer:
brilliants [131]4 years ago
8 0

Answer:

g_{planet} = \frac{3}{2}g

Explanation:

As we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

now we know that mass is the product of density and volume

so we will have

M = \rho \times \frac{4}{3}\pi R^3

Now we have

g = \frac{G(\rho \frac{4}{3}\pi R^3)}{R^2}

g = \frac{4}{3}\rho \pi R G

now size of new planet is half that of size of Earth and the density is 3 times the density of Earth

so we have

g_{planet} = \frac{4}{3}(3\rho)\pi (\frac{R}{2}) G

g_{planet} = \frac{3}{2}g

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it is true

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Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/sthrougha horizontal tube with a 30mmdiameter. what
marusya05 [52]

The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

<h3>How to find the pressure drop in pascal?</h3>
  • We have the Poiseuille's formula,

                     Q=\frac{\pi r^4P}{8\beta l}

  • where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.
  • By substituting values and rearranging we will get the pressure drop as,

                  P=3.284Pascals

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4.

Learn more about the Poiseuille's formula here:

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3 0
1 year ago
During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshi
vladimir2022 [97]

Answer:

At a deceleration of 60g, or 60 times the acceleration due to gravity a person will travel a distance of 0.38 m before coing to a complete stop

Explanation:

The maximum acceleration of the airbag = 60 g, and the duration of the acceleration = 36 ms or 36/1000 s or 0.036 s

To find out how far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60g

we write out the equation of motion thus.

S = ut + 0.5at²

wgere

S = distance to come to complete stop

u = final velocoty = 0 m/s

a = acceleration = 60g = 60 × 9.81

t = time = 36 ms

as can be seen, the above equation calls up the given variable as a function of the required variable thus

S = 0×0.036 + 0.5×60×9.81×0.036² = 0.38 m

At 60g, a person will travel a distance of 0.38 m before coing to a complete stop

7 0
3 years ago
He does whatever a spider can. Spider-Man, who has a mass of 76 [kg], is clinging onto an inclined wall forming an inclination a
Aliun [14]

Answer:570.54 N

Explanation:

Given

mass of man=76 kg

\theta =50^{\circ}

As man is standing over inclined building therefore

its weight has two components i.e. sin and cos component

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F=mgcos\theta =76\times 9.8\times \sin 50

F=570.54 N

4 0
3 years ago
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