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Yakvenalex [24]
2 years ago
10

In our simple system, what type of energy was used?

Physics
1 answer:
seropon [69]2 years ago
6 0

Type of energy was used is kinetic energy.

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Elle is playing with a ball in a bus that moves in a straight line with constant velocity. What can you say about the motion of
kramer
Given that they are all on the same bus that is travelling in a straight line at the same velocity, when Elle throws the ball directly upwards, the ball will simply fall back to her. This is because the bus, Elle, and the ball are all travelling in the same direction and at the same speed. Among the choices, the correct answer is A.
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3 years ago
A 2.0-kg object is attached to a spring (k = 55.6 N/m) that hangs vertically from the ceiling. The object is displaced 0.045 m v
rusak2 [61]

Answer:

Maximum acceleration will be 1.251m/sec^2

Explanation:

We have given mass of the object m = 2 kg

Spring constant k = 55.6 N/m

Amplitude is given as A = 0.045 m

We know that maximum acceleration in SHM is given by

Maximum acceleration =A\omega ^2

We know that \omega ^2=\frac{k}{m}=\frac{55.6}{2}=27.8

So maximum acceleration = 27.8\times 0.045=1.251m/sec^2

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3 years ago
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The tension in the horizontal cord is 30N. Find the weight of the object.
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Making a drawing of the system, we will have two forces which are tension and the weight of the object. Balancing the forces present, we do as follows:

T = W
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2 years ago
Calculate the orbital speed (in m/s) of a satellite that circles the Earth with a time period of 12.00 hours. The mass of the Ea
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Answer:

v = 3869 m/s

Explanation:

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v = \sqrt{\frac{GM}{r}}

also we know that

time period of the revolution is given as

T = \frac{2\pi r}{v}

now from above equation we know that

T = \frac{2\pi (\frac{GM}{v^2})}{v}

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so we will have

v = (\frac{2\pi GM}{T})^{1/3}

now plug in all data in this equation

v = (\frac{2\pi (6.67 \times 10^{-11})(5.97 \times 10^{24})}{12 \times 3600})^{1/3}

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2 years ago
A double-slit experiment yields an interference pattern due to the path length difference from light traveling through one slit
Lapatulllka [165]

Answer:

Therefore the correct statement is B.

Explanation:

In the interference and diffraction phenomena, the natural wave of electromagnetic radiation must be taken into account, the wave front that advances towards the slit can be considered as when it reaches it behaves like a series of wave emitters, each slightly out of phase from the previous one, following the Huygens principle that states that each point is compiled as a source of secondary waves.

The sum of all these waves results in the diffraction curve of the slit that has the shape

      I = Io sin² θ /θ²

Where the angle is a function of the wavelength and the width of the slit.

From the above, the interference phenomenon can be treated as the sum of two diffraction phenomena displaced a distance equal to the separation of the slits (d)

Therefore the correct statement is B

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