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3 years ago

PLEASE I NEED HELP! AND DONT FREAKING SEND A LINK! I’ve already asked this question like 3 times and no ones answered.

Engineering

2 answers:

Dominik [7]3 years ago

6 0

Answer:

What does the difference mean exactly?

I calculated the Area to be 78.5 mm² and Resistance 0.00111465Ω for the first part. I don't understand what the question means.

NISA [10]3 years ago

4 0

I don’t know I’m trying to find the answer give me a second

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A flywheel performs each of these functions except: A. Contains a gear used for engine starting B. Smoothes engine operation C.

torisob [31]

Answer:

C. Provides lubrication to parts

Explanation:

Flywheel :

Flywheel is a device which stored the mechanical energy.This energy can be use when more energy required during any operation.Due to high moment of inertia of the flywheel it resist the change in the speed .The flywheel is attached to the crank shaft at the rear side of the engine.

The flywheel perform following function:

1. It connects the crankshaft and the transmission system.

2.It makes the engine operation smooth.

3.It contains gear and other parts of the engine.

But it can not provide lubrication.

C. Provides lubrication to parts

4 0

3 years ago

Water flows through a converging pipe at a mass flow rate of 25 kg/s. If the inside diameter of the pipes sections are 7.0 cm an

ser-zykov [4K]

Answer:

volumetric flow rate = $0.0251 m^3/s$

Velocity in pipe section 1 = $6.513m/s$

velocity in pipe section 2 = 12.79 m/s

Explanation:

We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.

The density of water is = 997 kg/m³

density = mass/ volume

since we are given the mass, therefore, the volume will be mass/density

25/997 = $0.0251 m^3/s$

volumetric flow rate = $0.0251 m^3/s$

Average velocity calculations:

Pipe section A:

cross-sectional area =

$\pi \times d^2\\=\pi \times 0.07^2 = 3.85\times10^{-3}m^2$

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

$velocity = 25/(997 \times 3.85\times10^{-3}) = 6.513m/s$

Pipe section B:

cross-sectional area =

$\pi \times d^2\\=\pi \times 0.05^2= 1.96\times10^{-3}m^2$

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

$velocity = 25/(997 \times 1.96\times10^{-3}) = 12.79m/s$

7 0

3 years ago

How would I find the Voltage across the open circuit

Nimfa-mama [501]

Answer:

Vab = 80V

Explanation:

The only current flowing in the circuit is supplied by the 100 V source. Its only load is the 40+60 ohm series circuit attached, so the current in that loop is (100V)/(40+60Ω) = 1A. That means V1 = (1A)(60Ω) = 60V.

Vab will be the sum of voltages around the right-side "loop" between terminals 'a' and 'b'. It is (working clockwise from terminal 'b') ...

Vab = -10V +60V +(0A×10Ω) +30V

Vab = 80V

3 0

2 years ago

How fast is a 2012 nissan sentra speed and acceleration

Alika [10]

Answer:

it has 15 horsepower to 300 horsepower and it weighs 2,906 to 3,131

Explanation:

its torque is 142 to 180

it has a inline 4 engine

there's a SE-R which has a turbo

4 0

3 years ago

A gas turbine receives a mixture having the following molar analysis: 10% CO2, 19% H2O, 71% N2 at 720 K, 0.35 MPa and a volumetr

Sliva [168]

Answer:

2074.2 KW

Explanation:

Determine power developed at steady state

First step : Determine mass flow rate ( m )

m / Mmax = ( AV )₁ P₁ / RT₁ -------------------- ( 1 )

 where : ( AV )₁ = 8.2 kg/s, P₁ = 0.35 * 10^6 N/m^2, R = 8.314 N.M / kmol , 

 T₁ = 720 K . 

insert values into equation 1

m = 0.1871 kmol/s ( mix )

Next : calculate power developed at steady state ( using ideal gas tables to get the h values of the gases )

W( power developed at steady state )

W = m [ Yco2 ( h1 - h2 )co2

Attached below is the remaining part of the detailed solution

4 0

3 years ago