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3 years ago

Why is magneisum a metal

Chemistry

1 answer:

Fofino [41]3 years ago

3 0

Answer:

Magnesium is known for a long time as the lighter structural metal in the industry, due to it's low weight and to it's capability of forming mechanically resistant alloys.

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Write an equation that shows the formation of the chloride ion from a neutral chlorine atom

jeka57 [31]

The gaining of electron by an atom results in the formation of anion shown by the negative charge on the atom whereas lose of electron results in the formation of cation shown by positive charge on the atom. The atom lose or gain electron to complete their octet and get stable in nature.

The chlorine atom will gain an electron and form chloride anion with one negative charge on it. The chloride ion is more stable in nature compared to the chlorine atom due to complete octet of chloride ion by gaining of electron.

Electronic configuration of chlorine atom is:

$[Ne]3s^{2}3p^{5}$

By gaining of one electron, electronic configuration of chloride ion is:

$[Ne]3s^{2}3p^{6}$

Thus, the equation that shows the formation of the chloride ion from a neutral chlorine atom is:

$Cl+1e^{-}\rightarrow Cl^{-}$

4 0

4 years ago

Which law relates to the ideal gas law?

professor190 [17]

Answer: The law that related the ideal gas law is $\frac{V_1}{n_1}=\frac{V_2}{n_2}$

Explanation:

There are 4 laws of gases:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

Mathematically,

$P_1V_1=P_2V_2$

Charles' Law: This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Gay-Lussac Law: This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Avogadro's Law: This law states that volume is directly proportional to number of moles at constant temperature and pressure.

Mathematically,

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

Hence, the law that related the ideal gas law is $\frac{V_1}{n_1}=\frac{V_2}{n_2}$

8 0

3 years ago

Read 2 more answers

Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=-0.136-(-0.76)=0.624V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}$

where,

$E_{cell}$ = electrode potential of the cell = 0.660 V

$E^o_{cell}$ = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=2.5\times 10^{-3}M$

$[Sn^{2+}]$ = ?

Putting values in above equation, we get:

$0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})$

$[Sn^{2+}]=9.0\times 10^{-3}M$

Hence, the concentration of $Sn^{2+}$ ions is $9.0\times 10^{-3}M$

3 0

3 years ago

Hi guys, my question is:

guapka [62]

Answer:

See Explanation Below

Explanation:

A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.

B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5

C) The rate will increase by 4 since you are doubling both you have to multiply them both.

8 0

3 years ago

Question 21 of 25

RideAnS [48]

Answer:

Explanation:

7 0

3 years ago

Why is magneisum a metal​

Why is magneisum a metal