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ivann1987 [24]
3 years ago
14

How long is breast milk good for out of the fridge?

Chemistry
2 answers:
Helen [10]3 years ago
4 0

Answer:

until it gets bright white or smells bad, then throw it out

Explanation:

Svetach [21]3 years ago
3 0

Answer:

6-8 hours if left in a room temperature area

4 hours if left in a heated area

24 hours if left in an insulated cooler with an ice pack

Explanation:

have a nice day <3

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Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling
Reil [10]

Answer:

The boiling  point of a 8.5 m solution of Mg3(PO4)2 in water is<u> 394.91 K.</u>

Explanation:

The formula for molal boiling Point elevation is :

\Delta T_{b} = iK_{b}m

\Delta T_{b} = elevation in boiling Point

K_{b} = Boiling point constant( ebullioscopic constant)

m = molality of the solution

<em>i =</em> Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

In solution Mg3(PO4)2 dissociates as follow :

Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

Total ions = 5

<em>i =</em> Van't Hoff Factor = 5

m = 8.5 m

K_{b} = 0.512 °C/m

Insert the values and calculate temperature change:

\Delta T_{b} = iK_{b}m

\Delta T_{b} = 5\times 0.512\times 8.5

\Delta T_{b} = 21.76 K

Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K

\Delta T_{b} = T_{b} - T_{b}_{pure}

T_{b}_{pure} = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

8 0
3 years ago
Is milk a solution, colloid, suspension, or a compound?
allsm [11]
Milk is a colloid system
3 0
3 years ago
What is the freezing point (in degrees Celcius) of 4.14 kg of water if it contains 235.1 g of butanol, C 4 H 9 O H
Karolina [17]

Answer:

Explanation:

Molal freezing point depression constant of butanol Kf = 8.37⁰C /m

ΔTf = Kf x m , m is no of moles of solute per kg of solvent .

mol weight of butanol = 70 g

235.1 g of butanol = 235.1 / 70 = 3.3585 moles

3.3585 moles of butanol dissolved in 4.14 kg of water .

ΔTf = 8.37 x 3.3585 / 4.14

= 6.79⁰C

Depression in freezing point = 6.79

freezing point of solution = - 6.79⁰C .

5 0
3 years ago
Calculate the mass of 12.3 moles of MgSO4.​
Afina-wow [57]

Answer:

614 034 kg

Explanation:

n = m/Mm

m = n * Mm

Mm(MgSO4) = 1 * 24.3 * 1 * 32.1 * 4 * 16 = 49921.92

m = 12.3 * 49921.92

m = 614 034 kg

8 0
3 years ago
Read 2 more answers
What do the rows of the periodic table periodic table indicate
Tatiana [17]

Answer:

The rows on the periodic table are called periods. All the elements in a period have valence electrons in the same shell. The number of valence electrons increases from left to right in the period. When the shell is full, a new row is started and the process repeats.

<h2>I hope it helps plz let me know if it is right or wrong.</h2>

6 0
3 years ago
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