How did you post this pic?
Answer:

Explanation:
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In this case, since this is a problem in which the pressure of the gas remains constant, we can use the Charles' law as a directly proportional relationship between temperature (in Kelvins) and volume given by:

Thus, solving for the final volume as the temperature is decreased to -80.00 °C, we obtain:


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The given functions were

Before we can evaluate
we need to find an expression for
.
This is the composition of the two functions.
means
becomes an input for
. This means that;

So we need to substitute,
wherever we see
in 

We expand the bracket to obtain;

Simplify to obtain;


Now we substittute
in to
to obtain,



Hence, the value of
is
.
Answer:
Trimethylacetaldehyde
Explanation:
For the <u>unknow compound</u> we have a molar mass of 86 g/mol. We have an even value for the mass, so the compound does <u>not have nitrogen</u> and we can have several posibilities:
A) 
B) 
C) 
D) 
If we check the IR info a signal in 1730 cm-1 appears, this indicates that we have an <u>oxo group</u> (C=O). So, the D option can be discarded. The groups that can have the oxo group are: Carboxylic acids, <u>Ketones and aldehydes</u>.
We don have a signal in 3000 cm-1, so the carboxylic acid can be discarded. Now, is we check the info for the 1H NMR we only have 2 signals. If we only have 2 we will have a very<u> symmetric compound</u>.
By trial an error the find the compound <u>Trimethylacetaldehyde</u> (Figure 1).