Answer:
Characteristic time τ=20 s
When V = 15 m/s
t = 6.66 s
When V = 10 m/s
t = 20 s
When V = 5 m/s
t = 60 s
Explanation:
Given that
c=0.20 N/m(m/s)2
m = 80 kg
Vo=20m/s
Characteristic time τ=m/cvo.
Characteristic time τ=20 s
We know that velocity after t time given as follows
When V = 15 m/s
t = 6.66 s
When V = 10 m/s
t = 20 s
When V = 5 m/s
t = 60 s
Insight and umbra are the answers to these questions
Answer:
Explanation:
First of all, we need to calculate the energy of the x-ray photon emitted during the transition from K-shell to L-shell, and this energy is equal to the difference in energy between the two levels:
Converting into Joules,
Now we know that the energy of the photon is related to its wavelength by:
where
h is the Planck constant
c is the speed of light
is the wavelength
Re-arranging the equation for , we find
The object in the lower orbit will move faster in its orbit, and will have a shorter orbital period. None of that depends on their masses either.
Answer:
Explanation:
The magnitude of the electrostatic force between two charges is given by the equation:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
And the force is:
- Attractive if the charges have opposite sign
- Repulsive if the charges have same sign
In this problem, we have:
F = 3 N is the force between the proton and the electron
is the magnitude of the charge of the proton and the electron
Therefore, solving for r, we find the separation between the two particles: