Answer:
v = 18.84 m/s
Explanation:
Let the question says,"The blade of a 0.30 m diameter fan rotates 1200 rev / min. calculate the tangential speed."
It is given that,
Diameter of a blade of fan is 0.3 m
Angular velocity of the fan is 1200 rev/min or 125.66 rad/s
We need to find the tangential speed of the fan. The relation is given by :
r is radius of fan
So, the tangential velocity is 18.84 m/s.
Answer:
the magnitude of Vpg = 493.711 km/h
Explanation:
given data
speed Vpg = 560 km/h
speed Vwg = 80 km/h
solution
we get here magnitude of the plane velocity w.r.t. ground is
we know that the Vpg = Vpw + Vwg .....................1
writing the component of the velocity that is
Vpw = (0 km/h î - 560 km/h j )
Vwg = (80 cos 45 km/h î + 80 sin 45 km/h j)
adding these
Vpg = (0+80 cos 45 km/h ) î + ( -560 + 80 sin 45 km/h j)i
Vpg = (42.025 ) î (-491.92 km/h)j
now we take magnitude
the magnitude of Vpg =
the magnitude of Vpg = 493.711 km/h