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wariber [46]
2 years ago
5

Who was the first president of Nigeria​

Physics
2 answers:
kogti [31]2 years ago
7 0

Answer:

Nnamdi Benjamin Azikiwe,

Explanation:

miv72 [106K]2 years ago
6 0

Answer:

Alhaji Abubakar Tafawa Balewa was the first president of Nigeria

Explanation:

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Two ice skaters, each with a mass of 72.0 kg, are skating at 5.45 m/s when they collide and stick together. If the angle between
Rudiy27

Answer:

The skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.

Explanation:

To solve the problem it is necessary to go back to the theory of conservation of momentum, specifically in relation to the collision of bodies. In this case both have different addresses, consideration that will be understood later.

By definition it is known that the conservation of the moment is given by:

m_1v_1+m_2v_2=(m_1+m_2)v_f

Our values are given by,

m_1=m_2=72Kg

As the skater 1 run in x direction, there is not component in Y direction. Then,

Skate 1:

v_{x1}=5.45m/s

v_{y1}=0

Skate 2:

v_{x2} = 5.45*cos105= -1.41m/s

v_{y2} = 5.45*sin105 = 5.26m/s

Then, if we applying the formula in X direction:

m_1v_{x1}+m_2v_{x2}=(m_1+m_2)v_{fx}

75*5.45-75*1.41=(75+75)v_{fx}

Re-arrange and solving for v_{fx}

v_{fx}=\frac{4.04}{2}

v_{fx}=2.02m/s

Now applying the formula in Y direction:

m_1v_{y1}+m_2v_{y2}=(m_1+m_2)v_{fy}

0+75*5.25=(75+75)v_{fy}

v_{fy}=\frac{5.25}{2}

v_{fy}=2.63m/s

Therefore the skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.

6 0
2 years ago
I need help putting these in the right place!!
kolezko [41]
Any photos so i can help you with that?
6 0
3 years ago
Consider two waves X and Y traveling in the same medium. The two carry the same amount of energy per unit time, but X has one-se
RideAnS [48]

Answer:

7 / 1

Explanation:

The ratio of their amplitude = one-seventh and the ratio of their amplitude = the ratio of their wavelength

Ax / Ay = λx / λy  = 1 / 7

λy / λx = 7 / 1

7 0
3 years ago
Can someone help me with these problems? ​
Paladinen [302]
120/60= 2m per s
220/55= 4m per s
720/80= 9m per s
Fastest run: 3rd run
Speed: 9m per s
Slowest: 1st run
Speed: 2m per s

3 0
1 year ago
A 60kg student is 5m from a 120kg door, how much gravitational forces act between the two?
slavikrds [6]

Gravitational force = G · m₁ · m₂ / r²

' G ' is the 'universal gravitational constant, 6.673 x 10⁻¹¹ m³/kg-s²

m₁ = 60 kg

m₂ = 120 kg

r = 5 m

F = (6.673 x 10⁻¹¹ m³/kg-sec²) · (60 kg) · (120 kg) / (5m)²

F = (6.673 x 10⁻¹¹ · 60 · 120 / 25) · (m³ · kg · kg / kg · s² · m²)

F = 1.922 x 10⁻⁸ (kg · m / s²)

<em>F = 1.922 x 10⁻⁸ Newton</em>  (about 0.0000000692 ounce of force)

7 0
3 years ago
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