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sesenic [268]
2 years ago
14

What is the magnitude of the speed of a

Engineering
1 answer:
Mars2501 [29]2 years ago
6 0

The equatorial diameter of the earth is 12,756 km.

Therefore the equatorial radius is

r = 12756/2 = 6378 km.

The angular velocity of the earth is  

ω = (2π radians)/(24 hours) = 0.2618 rad/h

The tangential velocity of a person at the equator is

v = rω

  = (6378 km)*( 0.2618  rad/h)

  =  1670 km/h

Answer: 1670 km/h

I hope this helps you.

Brainly, thanks you, rating are all appreciated greatly!

Smile and have an amazing day ; )

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Answer:

Check the explanation

Explanation:

Code

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