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2 years ago

What is the magnitude of the speed of a

Engineering

1 answer:

Mars2501 [29]2 years ago

6 0

The equatorial diameter of the earth is 12,756 km.

Therefore the equatorial radius is

r = 12756/2 = 6378 km.

The angular velocity of the earth is

ω = (2π radians)/(24 hours) = 0.2618 rad/h

The tangential velocity of a person at the equator is

v = rω

= (6378 km)*( 0.2618 rad/h)

= 1670 km/h

Answer: 1670 km/h

I hope this helps you.

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Please help me with this. Plzzz.

Drupady [299]

Answer:

450,000m = 450km = 4.5E5

32,600,000W = 32.6MW = 3.26E7

59,700,000,000cal = 59.7Gcal = 5.97E10

0.000000083s = 83ns = 8.3E-8

35,000Ω = 35kΩ = 3.5E4

Explanation:

Giga = 1,000,000,000

Mega = 1,000,000

kilo = 1,000

unit = 1

deci = .1

centi = .01

milli = .001

micro = .000001

nano = .0000000001

pico = .000000000001

You should be able to look at these and convert between them in seconds if you want to pursue anything in engineering.

7 0

3 years ago

Steam at 75 kPa and 8 percent quality is contained in a spring-loaded piston–cylinder device, as shown in Figure, with an initia

Rashid [163]

The heat transferred to and the work produced by the steam during this process is 13781.618 kJ/kg

<h3>How to calcultae the heat?</h3>

The Net Change in Enthalpy will be:

= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg

Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)

= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

From the First Law of Thermodynamics, Q = U + W

So, Heat Transfer = Change in Internal Energy + Work Done

= 13331.618 + 450

Q = 13781.618 kJ/kg

Learn more about heat on:

brainly.com/question/13439286

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6 0

1 year ago

Calculate the rate at which body heat is conducted through the clothing of a skier in a steady- state process, given the followi

olga2289 [7]

Answer:

230.4W

Explanation:

Heat transfer by conduction consists of the transport of energy in the form of heat through solids, in this case a jacket.

the equation is as follows

$Q=\frac{KA(T2-T1)}{L} \\$

Where

Q=heat

k=conductivity=0.04

A=Area=1.8m^2

T2=33C

T1=1C

L=thickness=1cm=0.01m $Q=\frac{(0.04)(1.8m^2)(33-1)}{0.01m}$

Q=230.4W

the skier loses heat at the rate of 230.4W

4 0

3 years ago

A horizontal pipe has an abrupt expansion from D1 5 8 cm to D2 5 16 cm. The water velocity in the smaller section is 10 m/s and

anyanavicka [17]

Answer: Explanation: Application of the bernoulli's equation comes in from conservation of mass flow. The cross sectional area of the two pipes are calculated. from A = πD²/4 The velocity of water from conservation of mass flow is also calculated ; V2 = Ac1V1/Ac2 The Loss coefficient is then calculated from KL = (1 - Ac1²/Ac2²)² Then the head Loss (hL) is calculated The detailed calculated and appropriate steps is as shown in the attached files.

5 0

2 years ago

How many hours should it take an articulated wheel loader equipped with a 4-yd^3 bucket to load 3000 yd^3 of gravel (average mat

densk [106]

Answer:

17 hours 15 minutes

Explanation:

See attached picture.

4 0

3 years ago