Answer:
The molar average velocity is 0.0588 cm/s
The N₂ diffusion velocity relative to the mole average velocity is -0.1428 cm/s
The molar diffusional flux of N₂ is -3.9x10⁻³
Explanation:
Given data:
T = temperature = 265 K
O₂ = 25%
N₂ = 60%
CO₂ = 15%
vO₂ = -0.084 cm/s
vN₂ = 0.12 cm/s
vCO₂ = 0.052 cm/s
The molar average velocity is equal:
The N₂ diffusion velocity relative to the molar average velocity is:
The molar diffusional flux of N₂ is:
Answer:
The concentration of KOH is 0.186 M
Explanation:
First things first, we need too write out the balanced equation between HBr and KOH.
This is given as;
KOH (aq) + HBr (aq) → KBr (aq) + H2O (l)
From the reaction above, we can tell that it takes 1 mole of KOH to react with 1 mole of HBr.
We use the acid base formular in calculating unknown concentrations. This is given as;
where;
Ca = Concentration of acid
Va = Volume of acid
Cb = Concentration of base
Vb = Volume of base
na = Number of moles of acid
nb = Number of moles of base
KOH is the base and HBr is acid.
Hence;
Ca = 0.225
Va = 35
Cb = ?
Vb = 42.3
na = 1
nb = 1
Making Cb subject of formular we have;
Cb = (0.225 * 35 * 1) / (42.3 * 1)
Cb = 0.186 M