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LekaFEV [45]
2 years ago
15

I’m building a pc, but I only have 2 sata cables. What are the other required cables to connect to or parts, such as the gpu?

Engineering
2 answers:
galben [10]2 years ago
5 0

I don't know it but I'm just doing it for points

Usimov [2.4K]2 years ago
3 0

Answer:

You would also need power cables.

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What is 39483048^349374*3948048/3i4u4
Verizon [17]

Answer:

1.  3.81813506×10^2^9

2.  1.71479428×10^6^5

3.  9.38483383×10^2^6

4.  1.150847×10^2^9

Explanation:

Feel free to give brainliest

Have a great day!

3 0
2 years ago
Which traditional subject is part of construction management or construction science syllabi?
N76 [4]

Answer:mathematics

Explanation:

4 0
3 years ago
Why is it important to keep hand tools free of oil and grease?
Bezzdna [24]

Answer:

keeps it from rusting

Explanation:

5 0
3 years ago
A __________ is a single lane used by drivers to enter and exit a freeway. a) Climbing lane b) Weave lane c) Thru lane d) Offset
Rufina [12.5K]

A Weave lane is a single lane used by drivers to enter and exit a freeway.

<h3>What is this lane about?</h3>

Weave lanes are known to be lanes that acts as an entrance and exits for a lot of cars in highways.

Hence, one can say that A Weave lane is a single lane used by drivers to enter and exit a freeway.

Learn more about Weave lane from

brainly.com/question/10828527

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6 0
1 year ago
. The flexure strength test was performed on a concrete beam having a cross section of 0.15m by 0.15m and a span of 0.45m. If th
ivann1987 [24]

Answer:

σ =5.39Mpa

Explanation:

step one:

The flexure strength is defined as the tendency with which unreinforced concrete yield to bending forces

Flexural strength test Flexural strength is calculated using the equation:

σ = FL/ (bd^2 )----------1

Where

σ = Flexural strength of concrete in Mpa

F= Failure load (in N).

L= Effective span of the beam

b= Breadth of the beam

step two:

Given data

F=40.45 kN= 40450N

b=0.15m

d=0.15m

L=0.45m

step three:

substituting into the expression we have

σ = 40450*0.45/ (0.15*0.15^2 )

σ =18202.5/ (0.15*0.15^2 )

σ =18202.5/ (0.15*0.0225 )

σ =18202.5/0.003375

σ =5393333.3

σ =5393333.3/1000000

σ =5.39Mpa

Therefore the flexure strength of the concrete is 5.39Mpa

5 0
3 years ago
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