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LekaFEV [45]
2 years ago
15

I’m building a pc, but I only have 2 sata cables. What are the other required cables to connect to or parts, such as the gpu?

Engineering
2 answers:
galben [10]2 years ago
5 0

I don't know it but I'm just doing it for points

Usimov [2.4K]2 years ago
3 0

Answer:

You would also need power cables.

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An aluminum heat sink (k = 240 W/m-K) used to cool an array of electronic chips consists of a square channel of inner width w =
OverLord2011 [107]

Answer:

Explanation: see attachment below

8 0
3 years ago
Read 2 more answers
A piston-cylinder device contains 0.15 kg of air initially at 2 MPa and 350 °C. The air is first expanded isothermally to 500 kP
Semmy [17]

Answer:

Isothermal  expansion W₁ =-37198.9 J

Polytropic Compression W₂ =-34872.82 J

Isobaric Compression W₃ =  -6974.566 J

The net work for the cycle = -79046.29 J

Explanation:

Mass of air = 0.15 kg = 150 g

Molar mass = 28.9647 g/mol

Number of moles = 150 g /28.9647 g/mol = 5.179 moles of air

PV = nRT therefrore V = nRT/(P) = 5.179*8.314*(350+273.15)/(2×10⁶) = 0.0134167 m³

For isothermal expansion we have

P₁V₁ = P₂V₂ or V₂ = P₁V₁/P₂ = 2×10⁶*0.0134167 / (5×10⁵) = 0.0536668 m³

Therefore work done

W₁ = -nRTln(V₂/V₁) = -26833ln(4) = -37198.9 J

Stage 2

Compression polytropically we have

\frac{P_2}{P_3} = (\frac{V_3}{V_2} )^n  where P₃ = 2 MPa

Therefore V₃ = (\frac{1}{4} )^{\frac{1}{1.2} }*V_2  = 1.6904×10⁻² m³

Work = W₂ = \frac{P_2V_2-P_3V_3}{n-1} =  -34872.82 J

\frac{P_2}{P_3} = (\frac{T_2}{T_3} )^\frac{n}{n-1}     or T₃ = T_2*(\frac{P_3}{P_2})^\frac{n-1}{n} = 785.12 K

Isobaric compression we have  thus

Work done W₃ = P(V₁ -V₃) = -6974.566 J

Total work = W₁ + W₂ + W₃ = -37198.9 J + -34872.82 J + -6974.566 J = -79046.29 J

7 0
3 years ago
Automobile engines normally have
Virty [35]

Answer:

Depending on the vehicle, there are typically between two and 12 cylinders in its engine, with a piston moving up and down in each.

Explanation:

hmu if you need more help! :)

5 0
2 years ago
Calculate the number of vacancies per cubic meter for some metal, M, at 783°C. The energy for vacancy formation is 0.95 eV/atom,
djyliett [7]

Answer:

Following are the solution to this question:

Explanation:

The number of vacancies by the cubic meter is determined.  

N_V =N exp(\frac{Q_v}{kT})

      = \frac{N_A \rho}{A} exp (\frac{Q_v}{kT})

      =  \frac{6.022 \times 10^{23} \times 6.10}{43.41} \exp(\frac{-0.95}{8.62\times 10^{-5} \times (783+273)})\\\\=  \frac{36.7342 \times 10^{23}}{43.41} \exp(\frac{-0.95}{0.0313626})\\\\=  0.846215158 \times 10^{23} \exp(-30.290856)\\\\

      =1.57 \times 10^{25} \ cm^{-3}

7 0
3 years ago
The penalty for littering 15 lb or less is _____.<br> A. $25<br> B. $50<br> C. $100<br> D. $150
Marina CMI [18]

Answer:

D the closest

Explanation:

i looked it up and 8t says 200

5 0
3 years ago
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