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faust18 [17]
3 years ago
14

ITS MY WORK FROM SCIENCE, AND I NEED THAT FOR NOW, I DONT EVEN KNOW HOW TO ANSWER THAT​

Chemistry
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

TEEHEE

Explanation:

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Limestone (CaCO₃) is used to remove acidic pollutants from smokestack flue gases. It is heated to form lime (CaO), which reacts
Alex

To completely eliminate all of the SO2 produced by coal burning, 1250.62 kg of CaCO3 are required.

Equation

CaCO₃ --->CaO + CO2

2 CaO +2 SO2 ----> 2 CaS + 3O2

overall reaction

2 CaCO₃ +2 SO2 ---> 2 CaS + 3O2 + 2CO2

m(S)=8,5 x 10^{4}*0.0033=280.5 kg

n(SO2)= m/Ar(S) = 8,75 x 10^{3}mol

n(CaCO3 needed) = n(SO2) / percent yield

n(CaCO3 needed) = 8.75 x 10^{3}mol / 0.7

​n(CaCO3 needed)= 1.25 x 10 ^4 mol

m(CaCO3 needed) = n x Mr = 1250.62kg

To completely eliminate all of the SO2 produced by coal burning, 1250.62 kg of CaCO3 are required.

<h3>Where Is Limestone Found?</h3>

Numerous locations that produce limestone have been recognized by geologists throughout the world. Between 30o N and 30o S latitude, the most of them are in shallow waters. The Caribbean Sea, Indian Ocean, Persian Gulf, and the Gulf of Mexico are the most well-known shallow water locations.

learn more about limestone here

brainly.com/question/15148363

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5 0
2 years ago
For which molecule can the bonding be described in terms of sp3 hybrid orbitals of the central atom?
julia-pushkina [17]
I believe that the answer is C.PCI5
6 0
4 years ago
In an exothermic reaction, the energy of the reactants is greater than the energy of
mojhsa [17]

Answer:

H

Explanation:

If the energy content in the reactants is higher than the products, that means that the reaction must be giving away energy. So, in other words, chemical energy from the reactants must be released as heat.

6 0
3 years ago
How many moles are in 281 g of Ca(OH)2?
Natasha_Volkova [10]

Answer:

3.79 moles

Explanation:

To convert moles to gams of a substance we need to find the molar mass of the substance. For Ca(OH)₂ th molar mass is:

1Ca = 40.08g/mol

2O = 2*16g/mol = 32g/mol

2H = 2*1.01g/mol = 2.02g/mol

The molar mass is:

40.08g/mol + 32g/mol + 2.02g/mol = <em>74.1g/mol</em>

<em />

And moles are:

281g * (1mol / 74.1g) =

<h3>3.79 moles</h3>
5 0
3 years ago
A chemist wishing to do an experiment requiring 47-Ca2+ (half-life = 4.5 days) needs 5.0 μg of the nuclide. What mass of 47-CaCO
NARA [144]

Answer:

5.8μg

Explanation:

According to the rate or decay law:

N/N₀ = exp(-λt)------------------------------- (1)

Where N = Current quantity,  μg

            N₀ = Original quantity, μg

             λ= Decay constant day⁻¹

              t =  time in days

Since the half life is 4.5 days, we can calculate the  λ from (1) by  substituting N/N₀ = 0.5

0.5 = exp (-4.5λ)

ln 0.5  = -4.5λ

-0.6931 = -4.5λ

λ =   -0.6931 /-4.5

  =0.1540 day⁻¹

Substituting into (1)  we have :

N/N₀ = exp(-0.154t)----------------------------- (2)

To receive 5.0 μg of the nuclide with a delivery time of 24 hours or 1 day:

N = 5.0 μg

N₀ = Unknown

t = 1 day

Substituting into (2) we have

[5/N₀]   = exp (-0.154 x 1)

    5/N₀        = 0.8572

N₀  =  5/0.8572

     =    5.8329μg

    ≈     5.8μg

The Chemist must order 5.8μg  of 47-CaCO3

6 0
3 years ago
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