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faust18 [17]
3 years ago
14

ITS MY WORK FROM SCIENCE, AND I NEED THAT FOR NOW, I DONT EVEN KNOW HOW TO ANSWER THAT​

Chemistry
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

TEEHEE

Explanation:

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Fill in the following table.
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3 0
2 years ago
Using chemical equation to find moles of product from moles of reactant
Zolol [24]

Answer:

0.21 mole of C8H18.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Next, we shall determine the number of mole of C8H18 that reacted and the number of mole water (H2O) produced from the balanced equation.

This is illustrated below:

From the balanced equation above,

2 moles of C8H18 reacted to produce 18 moles of H2O.

Finally, we shall determine the number of mole C8H18 needed to produce 1.90 moles of H2O.

This can be obtained as follow:

From the balanced equation above,

2 moles of C8H18 reacted to produce 18 moles of H2O.

Therefore, Xmol of C8H18 will react to produce 1.90 moles of H2O i.e

Xmol of C8H18 = (2 × 1.90)/18

Xmol of C8H18 = 0.21 mole

Thus, 0.21 mole of C8H18 is needed for the reaction.

5 0
3 years ago
A student has a 0.00124 M HCl (aq) solution and she titrates 25.00 mL of this solution against an unknown potassium hydroxide so
malfutka [58]

Answer:

The Molarity of KOH is

7,01.10^{-4}M

Explanation:

The endpoint indicates the volume necessary to neutralize the moles of acid.

In other words, the point at which the moles of both solutions are the same.

M_{(HCl)}V_{HCl}=n\\ \\M_{(KOH)}V_{KOH}=n

we match these equations and find the concentration of KOH

M_{(HCl)}. V_{(HCl)} =M_{(KOH)} .V_{(KOH)}\\ \\M_{(KOH)}=\frac{M_{(HCl)}. V_{(HCl)}}{V_{(KOH)}} \\\\M_{(KOH) =\frac{(25mL)(0,00124m)}{(44,25mL)}\\\\

M_{(KOH)}=7,01.10^{-4}

5 0
3 years ago
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