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Alex787 [66]
3 years ago
12

Determine the amount of grams present in 3.25x1024 atoms of Lithium.

Chemistry
1 answer:
Sveta_85 [38]3 years ago
4 0
When converted to a household measurement, 9 kilograms is approximately equal to a
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What is the difference between a substance at low temperature and one at high temperature
givi [52]

Answer:

Explained below.

Explanation:

A substance at low temperature simply means that the average energy of molecular motion in that substance is low while at higher temperature, the average energy of molecular ml tip in that substance is high.

4 0
3 years ago
Upon balancing the equation what is the smallest possible integers that goes in front O₂? HBr + O₂ ➞ H₂O + Br₂ *
Leokris [45]

Answer:

1

Explanation:

4 HBr + O2 → 2H 20 + 2Br 2

...............

7 0
2 years ago
Read 2 more answers
The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati
a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.80M^{-1}s^{-1}

t = time taken  = 95 s

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0
3 years ago
How does an objects speed affect its kinetic energy?​
rewona [7]
Because it’s kinetic energy INCREASES the speed
8 0
3 years ago
One problem with elimination reactions is that mixtures of products are often formed. For example, treatment of 2-bromo-2-methyl
NikAS [45]

Answer:

Structures are given below.

Explanation:

  • Treatment of 2-bromo-2-methylbutane with KOH in ethanol will give elimination of HBr through E2 mechanism.
  • H atoms adjacent to Br will be eliminated.
  • 2-bromo-2-methylbutane has two possible adjacent H atoms that can be eliminated giving mixture of products.
  • Product of this elimination reaction is alkene. Here saytzeff fule is followed during elimination. So most substituted alkene will be major product.
  • Structure of alkenes are given below.

5 0
3 years ago
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