Question

A student is asked to calculate the centripetal acceleration of a hummingbird that makes a complete circle in 0.43 seconds. If the circle has a radius of 0.25 m, what is
the correct setup for determining the centripetal acceleration of the hummingbird?
(3.65m/s)2/0.25m
(3.65m/s)2-0.43
O (0.435)2 / 25m
O (0.432.25m

Answer 1

The centripetal acceleration of the hummingbird is $\frac{(3.65)^2}{0.25} = 53.29 \ m/s^2$

The given parameters;

• time of motion of the hummingbird, t = 0.43 s
• radius of the circle, r = 0.25 m
• number of revolution of the hummingbird = 1 rev per 0.43 s

The angular speed of the hummingbird is calculated as follows;

$\omega = \frac{1 \ rev}{0.43 \ s} \times \frac{2\pi \ rad}{1 \ rev} =14.61 \ rad/s$

The linear speed of the hummingbird is calculated as follows;

v = ωr

v = 14.61 x 0.25

v = 3.65 m/s

The centripetal acceleration of the hummingbird is calculated as follows;

$a_c = \frac{v^2}{r} \\\\a_c = \frac{(3.65)^2}{0.25} \\\\a_c = 53.29\ m/s^2$

Thus, the centripetal acceleration of the hummingbird is $\frac{(3.65)^2}{0.25} = 53.29 \ m/s^2$

Learn more here:brainly.com/question/11700262