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3 years ago

Can somebody please help me with this question please

Chemistry

1 answer:

lys-0071 [83]3 years ago

4 0

Answer: D

Explanation:

An object can store energy as the result of its position. For example, the heavy ball of a demolition machine is storing energy when it is held at an elevated position. This stored energy of position is referred to as potential energy. Similarly, a drawn bow is able to store energy as the result of its position. When assuming its usual position (i.e., when not drawn), there is no energy stored in the bow. Yet when its position is altered from its usual equilibrium position, the bow is able to store energy by virtue of its position. This stored energy of position is referred to as potential energy. Potential energy is the stored energy of position possessed by an object. https://taraenergy.com/blog/an-introduction-to-potential-energy/

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2 years ago

Which noble gas has the same electron configuration as the oxygen in a water molecule?

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4 years ago

A 51.9 g sample of quartz is put into a calorimeter (see sketch at right) that contains 300.0 g of water. The quartz sample star

Trava [24]

Answer:

The specific heat capacity of quartz is 0.71 J/g°C.

Explanation:

Heat lost by quartz will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of quartz= $m_1=51.9 g$

Specific heat capacity of quartz= $c_1=?$

Initial temperature of the quartz= $T_1=97.8^oC$

Final temperature = $T_2=T = 19.3^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=300.0 g$

Specific heat capacity of water= $c_2=4.18 J/g^oC$

Initial temperature of the water = $T_3=17.0 ^oC$

Final temperature of water = $T_2=T=19.3^oC$

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(51.9 gc_1\times (19.3^oC-97.8^oC))=300.0 g\times 4.18 J/g^oC\times (19.3^oC-170^oC)$

we get:

$c_1 =0.7079 J/g^oC\approx 0.71 J/g^oC$

The specific heat capacity of quartz is 0.71 J/g°C.

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3 years ago

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Answer:

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