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fiasKO [112]
2 years ago
5

 Lime is a basic substance which is sometimes put onto acidic soils to make them neutral.

Chemistry
1 answer:
earnstyle [38]2 years ago
5 0

Answer:

the correct answer is Blue

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Which of the following are indicators of a chemical change?
Ket [755]

Answer:

All unexpected changes: color change (two clear liquids make purple), temperature change, Odor change or formation, precipitate formation (solid forms), and the production of gas.

Explanation:

4 0
2 years ago
A weather map is an example of a
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C. Model. It's a graphical model that displays one or more weather elements. 
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2 years ago
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How many moles of SnF₂ will be produced along with 48 grams of H₂? *
KIM [24]

Answer: 24 moles of SnF_2 are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

{\text{Moles of}  H_2}=\frac{48g}{2g/mol}=24moles

Sn+2HF\rightarrow SnF_2+H_2

According to stoichiometry :

1 mole of H_2 is accompanied with = 1 mole of SnF_2

Thus 24 moles of H_2  is accompanied with =\frac{1}{1}\times 24=24moles  of SnF_2

Thus 24 moles of SnF_2 are produced.

8 0
2 years ago
At room temperature iodine is a solid and bromine is a liquid.
vichka [17]

Answer:

<u>Kinetic particle theory</u>

Arrangement and motion of solid particles

-> Solid particles are packed closely with each other in an orderly manner. They vibrate vigorously in their fixed positions.

Arrangement and motion of liquid particles

-> Liquid particles are packed less closely with each other as compared to solid particles in a disorderly manner. They move around in a random motion; sliding past each other.

3 0
3 years ago
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
3 years ago
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