Answer:
w = 132.57 rad / s
Explanation:
To solve this exercise we must define a system formed by the two discs, therefore the angular momentum is conserved
initial
L₀ = I₀ w₀
final
L_f = I w
how the moment is preserved
L₀ = L_f
I₀ w₀ = I w
the moment of inertia of disk 1 is
I₀ = ½ m₁ r₁²
The moment of inertia of the set is
I = I₀ + I₂
I = ½ m₁ r₁² + ½ m₂ r₂²
we substitute
½ m₁ r₁² w₀ = (½ m₁ r₁² + ½ m₂ r₂²) w
w = 
let's reduce the magnitudes to the SI system
w₀ = 30.0 rev / s (2π rad / 1 rev) = 188.5 rad / s
let's calculate
w = ( 
) 188.5
w = ( 
) 188.5
w = 132.57 rad / s
Answer:
The acceleration of the boxes is 1.5 ft/s²
The displacement of the boxes during the speed-up period is 0.1875 ft.
Explanation:
Hi there!
Let´s convert the 45 ft/min into ft/s:
45 ft/min · 1 min/ 60 s = 0.75 ft/s
It takes the belt 0.5 s to reach this speed. Then, the acceleration of the boxes will be:
a = v/t
Where:
a = acceleration.
v = velocity.
t = time.
a = 0.75 ft/s / 0.5 s
a = 1.5 ft/s²
The acceleration of the boxes is 1.5 ft/s²
The equation of displacement is the following:
x = x0 + v0 · t + 1/2 · a · t²
Where:
x = position of the boxes at time t.
x0 = initial position.
v0 = initial velocity.
t = time.
a = acceleration.
Since the origin of the frame of reference is located at the point where the boxes begin to move, x0 = 0. Since the boxes were initially at rest, v0 = 0. Then:
x = 1/2 · a · t²
x = 1/2 · 1.5 ft/s² · (0.5 s)²
x = 0. 1875 ft
The displacement of the boxes during the speed-up period is 0.1875 ft.
Answer:
The torque must be applied to the wheel is 15.7 N-m.
Explanation:
Given that,
Mass of the wheel of cylinder, m = 50 kg
Diameter of the wheel, d = 1 m
Radius, r = 0.5 m
Initial speed off the wheel is 0
Final angular speed of the wheel, 120 rev/min = 12.56 rad/s
Angular displacement, 
The torque is given by :
So, the torque must be applied to the wheel is 15.7 N-m.
The thermal energy keeps these two changing their temperature over time.
The surrounding temperature (environment) clearly effects the cold water AND the boiling water.
Eventually, both would reach an equilibrium in temperature. <span />
Julia margaret cameron used a short focal length lens that allowed only a small area of sharp focus. The effect that the lens like this produce would be Less Magnification and Wide Angle of view.
A lens having short focal length will produce Less Magnification and Wide Angle of view.
Short focal length gives a deeper depth of the present field in addition to the wide angle of view. They capture maximally that lies in their front of the camera to the infinity.
A lens with large focal length captures a narrow field band as compared to the one with short focal length.
The lower focal length shows the short depth of focus leading to less magnification.
Short focal length is determined by the radius of curvature of both the curvature of the lens, the medium of the surrounding and the refractive index of the lens given.
Focal length of camera shows how much band the camera is able to capture.
Learn more about Focal length here, brainly.com/question/16188698
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