The element vanadium had a line with a wavelength of 318.5 nm in its emission spectrum. What is the frequency of this line

Chemistry

1 answer:

Hunter-Best [27]2 years ago

7 0

The frequency of this line of vanadium is 9.38 x10 ^14 Hz.

Emission spectrum shows how the electron of an atom goes or moves from a higher to a lower energy level.

Now The energy of a photon is given by

E = hc/λ

where

h = Plank's constant = 6.626 x 10⁻³⁴ J s

c = speed of light= 3 x 10⁸ m/s

λ = wavelength = 318.5 x 10⁻⁹ m

Solving

E = (6.626 x 10⁻³⁴ J s x 3 x 10⁸ m/s) / 318.5 x 10⁻⁹ m

E =6.2166 x10 ^-19 J

Also, we know that energy is related to frequency by the equation

E =hf

Where;

h = Planks's constant

f = frequency of photon

Making frequency subject of the formulae

f = E/h

f =6.2166 x10 ^-19 J/ 6.626 x 10⁻³⁴ J s

f = 9.38 x10 ^14 Hz

See similar question and solution here:brainly.com/question/24630281

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Explanation:

The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.

Measurements > Density

Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:

$Specific\text{ gravity = }\frac{density\text{ of substance}}{density\text{ of reference substance}}$

The density of a substance is defined as the ratio between the mass and the volume of this substance:

$density=\frac{mass}{volume}$

Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:

$0.860=\frac{density\text{ of substance}}{1.00g/mL}\rightarrow density\text{ of substance = 0.860g/mL}$

Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.

Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment: