Answer:
The angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is <u>10°.</u>
Explanation:
Given:
Mass of the driver is, 
Radius of circular turn is, 
Linear speed of the car is, 
Since, the car makes a circular turn, the driver experiences a centripetal force radially inward towards the center of the circular turn. Also, the driver experiences a downward force due to her weight. Therefore, two forces act on the driver which are at right angles to each other.
The forces are:
1. Weight = 
2. Centripetal force, 'F', which is given as:

Now, the angle of the net force acting on the driver with respect to the vertical is given by the tan ratio of the centripetal force (Horizontal force) and the weight (Vertical force) and is shown in the triangle below. Thus,
°
Therefore, the angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is 10°.
Answer:
the final velocity of the car is 59.33 m/s [N]
Explanation:
Given;
acceleration of the car, a = 13 m/s²
initial velocity of the car, u = 120 km/h = 33.33 m/s
duration of the car motion, t = 2 s
The final velocity of the car in the same direction is calculated as follows;
v = u + at
where;
v is the final velocity of the car
v = 33.33 + 13 x 2
v = 59.33 m/s [N]
Therefore, the final velocity of the car is 59.33 m/s [N]
Centripetal force = (mv^2)/r
so r = (mv^2)/ force = 246500 / 1100 = 224 m
Answer:
Explanation:
To find the direction of this vector we need o find the angle that has a tangent of the y-component over the x-component:
but since we are in Q2 we have to add 180 degrees to that angle giving us 165.5 degrees
Because melting point<span> and </span>freezing point<span> describe the</span>same<span> transition of matter, in this case from liquid to solid (</span>freezing) or equivalently, from solid to liquid (melting<span>).</span>