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Gnoma [55]
3 years ago
15

Can someone help me pls Sorry if the photo is rubbish

Physics
2 answers:
cestrela7 [59]3 years ago
8 0

Answer:

Last option <u>F</u>

<u>mark</u><u> it</u><u> </u><u>brainliest</u><u> if</u><u> it</u><u> helps</u><u> you</u><u> ❤️</u>

yarga [219]3 years ago
5 0

Answer:

F

Explanation:

F is not a molecule, a molecule contains two or more cells. But F stands for fluorine, which I think is a singular cell.

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0<br> What is 33 C in absolute temperature? hs
AysviL [449]

Answer:

33 Celsius is 306.15 in absolute temperature

7 0
3 years ago
Why is a protective apron or lab coat important to use when working with acids?
Kipish [7]

Answer:

Acids break down fabrics and can cause burns if the acids are strong.

Explanation:

A protective apron or lab coat is important when working with acids because acids break down fabrics and can cause burns if the acids are strong.

  • An acid is a substance that interacts with water to produce excess hydroxonium ions in an aqueous solution.
  • A strong acid ionizes completely in solution.
  • When they come in contact with a fabric, they break them down violently.
  • So, if they come in contact with the skin, it causes a violent break down of body tissues.
  • The apron acts a protective layer.
4 0
3 years ago
Read 2 more answers
We want to design a cylindrical vacuum capacitor, with a given radius a for the outer cylindrical shell, that will be able to st
anastassius [24]

Solution :

a). Using Gauss's law :

  $E=\frac{Q}{4 \pi \epsilon_0r^2}$  ,    $b    .........(1)

Let $E=E_0,\ r=b$ in equation (1)

Therefore, $Q=4 \pi \epsilon_0b^2E_0$  .............(2)

$V_b-V_a = \int^a_b \vec E. d\vec l$

             $=\int^a_b E \ dx$

            $=\frac{Q}{4 \pi \epsilon_0} \int^a_b \frac{1}{x^2} \ dx$

            $=\frac{Q(a-b)}{4 \pi \epsilon_0 a b}$  ....................(3)

Therefore, $U=\frac{1}{2}Q \Delta V$

                     $=\frac{1}{2}(4 \pi \epsilon_0 b^2 E_0)\left(\frac{Q(a-b)}{4\pi \epsilon_0 a b}\right)$

                     $=\frac{4 \pi \epsilon_0}{2a} \ E^2_0 b^3(a-b)$  .............(4)

Now differentiating the equation (4) w.r.t. 'b', we get

$b=\frac{3}{4}a$  

Thus the radius for the inner cylinder conductor is $b=\frac{3}{4}a$

b). For the energy storage, substitute the radius in (4), we get

$U = 4 \pi\epsilon_0 \frac{27a^3E^2_0}{512}$

This is the amount of energy stored in the conductor.

8 0
3 years ago
Frank stands still while throwing a dart toward a target with a speed of 25 m/s.
fgiga [73]

ANSWER IS A)

THE SPEED IS 25 M/S FOR BOTH PEOPLE

9 0
3 years ago
Calculate the time it would take a motor with a power of 0.6kW to lift a suitcase of 20kg a distance of 50cm
True [87]

Answer:

0.163 s

Explanation:

Appying,

P = mgh/t................ Equation 1

Where P = power of the motor, m = mass of the suitcase, h = vertical distance, t = time, g = acceleration due to gravity.

make t the subject of the equation,

t = mgh/P................ Equation 2

Given: m = 20 kg, h = 50 cm = 0.5 m, P = 0.6 kW = 600 W

Constant: g = 9.8 m/s²

Substitute these values into equation 2

t = (20×0.5×9.8)/600

t = 0.163 s

7 0
3 years ago
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