Frank stands still while throwing a dart toward a target with a speed of 25 m/s.

Two different sources of radiation give the same dose equivalent in Sv. Does this mean that the radiation from each source has t

Alisiya [41]

The product of the dosage Gy and relative biological efficiency yields a radiation dose equivalent Sv (RBE).

Sv =dose in Gy * RBE Sv=dose in GyRBE

The quantity of ionising energy absorbed by 1 text kg1 kg of tissue is defined as a radiation dose Gy. While RBE is a measure of a specific dose's biological effect relative to the biological effect of an equal quantity of X rays.

<h3>What is radiation?</h3>

Radiation is energy that moves through space at the speed of light from a source. This energy is coupled with an electric and magnetic field, and it exhibits wave-like qualities. Radiation is sometimes known as "electromagnetic waves."

Nature has a diverse variety of electromagnetic radiation. One example is visible light.

X-rays and gamma rays are extremely energetic. They may take electrons from atoms when they engage with them, causing the atom to become ionised.

learn more about Radiation refer:

brainly.com/question/893656

#SPJ4

5 0

2 years ago

One form of energy can be _____ another type of energy.

kotegsom [21]

We can answer this one very quickly. From the Law of Conservation of Energy, we know that "Energy can't be created or destroyed.".

So that only leaves us one way to complete the sentence in this question:

"One form of energy can be transformed into another type of energy. " (B)

4 0

3 years ago

Automobile A and B are initially 30 m apart travelling in adjacent highway lanes at speeds VA = 14.4 km/hr., VB 23.4 km/hr. at t

marshall27 [118]

Answer:

x = 240 m

Explanation:

This is a kinematics exercise

Let's fix our frame of reference on car A

x = x₀ₐ+ v₀ₐ t + ½ aₐ t²

the initial position of car a is zero

x = 0 + v₀ₐ t + ½ 0.8 t²

for car B

x = x_{ob} + v_{ob} t - ½ a_b t²

car B's starting position is 30 m

x = 30 + v_{ob} t - ½ 0.4 t²

at the point where they meet, the position of the two vehicles is the same

0 + v₀ₐ t + ½ 0.8 t² = 30 + v_{ob} t - ½ 0.4 t²

let's reduce the speeds to the SI system

v₀ₐ = 14.4 km / h (1000 m / 1 km) (1h / 3600s) = 4 m / s

v_{ob} = 23.4 km / h = 6.5 m / s

4 t + 0.4 t² = 30 + 6.5 t - 0.2 t²

0.2 t² - 2.5 t - 30 = 0

t² - 12.5 t - 150 = 0

we solve the quadratic equation

t = $\frac{12.5 \pm \sqrt{12.5^2 + 4 \ 150} }{2}$

t = $\frac{12.5 \ \pm 27.5}{2}$

t₁ = 20 s

t₂ = -7.5 s

time must be a positive quantity so the correct result is t = 20 s

let's look for the distance

x = 4 t + ½ 0.8 t²

x = 4 20 + ½ 0.8 20²

x = 240 m

8 0

3 years ago

An overhead electric power line carries a maximum current of 125 A. What is the magnitude of the maximum magnetic field at a poi

BARSIC [14]

Answer:

B= 55.6×10^(-7) Tesla

Explanation:

B= μoI/(2πr)

B: magnetic field strength

μo: permeability of free space and is equal to 4π×10^(-7) T.m/A

r: distance from the wire

I : current in the wire

B= (4π×10^(-7)×125)/(2π×4.5)

B= 55.6×10^(-7) Tesla

3 0

3 years ago

Halleys comet has period of 75.3 years. Using Kepler’s third law, find it’s semimajor axis expressed in astronomical units?

natta225 [31]

Answer: 17.83 AU

Explanation:

According to Kepler’s Third Law of Planetary motion “The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. 

$T^{2}\propto a^{3}$ (1)

Talking in general, this law states a relation between the orbital period $T$ of a body (moon, planet, satellite, comet) orbiting a greater body in space with the size $a$ of its orbit.

However, if $T$ is measured in years, and $a$ is measured in astronomical units (equivalent to the distance between the Sun and the Earth: $1AU=1.5(10)^{8}km$ ), equation (1) becomes: