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Nitella [24]
3 years ago
7

1. What amount of ammonia (in moles) is produced by the reaction of 4.00 mol H2 with 3.00 mol Nz?

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
7 0
<h2>Answer:  6 moles</h2>

<h3>Explanation:</h3>

3 H₂    +    N₂   →   2 NH₃

   ↓            ↓

4 mol       3 mol

Since the moles of N₂ is the smaller of the two reactants, then N₂ is the limiting factor (the reactant that will decide how much ammonia is produced since it has the smaller amount of moles). ∴ we have to use it in calculating the number of moles of ammonia

The mole ratio of N₂ to NH₃ based on the balanced equation is 1 to 2.

∴ the moles of NH₃ = moles of N₂ × 2

                                =  3 moles × 2

                                = 6 moles

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The one with higher mass has a higher density because it fits more mass into the same amount of space (volume).

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3 years ago
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. W
nikklg [1K]

Answer:

There are 3 steps of this problem.

Explanation:

Step 1.

Wet steam at 1100 kPa expands at constant enthalpy to 101.33 kPa, where its temperature is 105°C.

Step 2.

Enthalpy of saturated liquid Haq = 781.124 J/g

Enthalpy of saturated vapour Hvap = 2779.7 J/g

Enthalpy of steam at 101.33 kPa and 105°C is H2= 2686.1 J/g

Step 3.

In constant enthalpy process, H1=H2 which means inlet enthalpy is equal to outlet enthalpy

So, H1=H2

     H2= (1-x)Haq+XHvap.........1

    Putting the values in 1

    2686.1(J/g) = {(1-x)x 781.124(J/g)} + {X x 2779.7 (J/g)}

                        = 781.124 (J/g) - x781.124 (J/g) = x2779.7 (J/g)

1904.976 (J/g) = x1998.576 (J/g)

                     x = 1904.976 (J/g)/1998.576 (J/g)

                     x = 0.953

So, the quality of the wet steam is 0.953

                   

7 0
3 years ago
Read 2 more answers
1.
Makovka662 [10]

Answer:

1) 70

2) conduction

3) The ground absorbs the solar radiation and

releases it throughout the later afternoon.

4) transpiration

5) convection

6) cumulonimbus

7) reflectivity of Earth’s surface

8) As temperature increases, air pressure

increases.

9) thermosphere

10) convection cells, pressure belts, and the

Coriolis effect

11) radiation

12) pollen

13) scattering

14) thermosphere

15) The different types of clouds are:

<u>cumulus:</u><em><u> </u></em><em>Cumulus clouds are clouds which have flat bases and are often described as "puffy", "cotton-like" or "fluffy" in appearance. Their name derives from the Latin cumulo-, meaning heap or pile. </em>

<u>cirrus</u><em>:</em><em> </em><em>Cirrus is a genus of atmospheric cloud generally characterized by thin, wispy strands, that typically appear white or light grey. The name is derived from the Latin word cirrus, meaning 'ringlet' or 'curling lock of hair'. Such a cloud can form at any altitude between 5,000 and 13,700 m above sea level.</em>

<u>stratus:</u><em> </em><em>Stratus clouds are low-level clouds characterized by horizontal layering with a uniform base, as opposed to convective or cumuliform clouds that are formed by rising thermals.</em>

<u>nimbus</u>: <em>Nimbostratus clouds are dark, grey, featureless layers of cloud, thick enough to block out the Sun and produce persistent rain. Height of base: 2,000 - 10,000 ft. Shape: Bands or areas of individual cells. Latin: nimbus - rainy cloud; stratus - flattened or spread out. Precipitation: Continuous rain or snow likely.</em>

16) the tradewinds

17) the location’s latitude

18) Cirrus clouds

19) the ozone layer

20) Global winds are created by both the spin of

the Earth (Coriolis effect) and the differences

in temperature between the equator and

the polar areas. These winds are often

grouped together as trade winds, easterlies,

and westerlies.

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the Oparin-Haldane hypothesis

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Explanation:

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An example of a double replacement chemical reaction takes place in batteries. In an alkaline battery, Manganese oxide reacts wi
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3 years ago
A chemist must dilute of aqueous sodium carbonate solution until the concentration falls to . He'll do this by adding distilled
Mademuasel [1]

The question is incomplete, complete question is :

A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate  solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

The final volume of the solution will be 0.236 L.

Explanation:

Concentration of sodium carbonate solution before dilution =M_1= 400 mM

Volume of sodium carbonate solution before dilution = V_1=73.9 mL

Concentration of sodium carbonate solution after dilution =M_2= 125 mM

Volume of sodium carbonate solution after dilution = V_2=?

Dilution equation is given by:

M_1V_1=M_2V_2

V_2=\frac{M_1V_1}{M_2}

V_2=\frac{400 mM\times 73.9 mL}{125 mM}= 236.48 mL\approx 236 mL

1 mL = 0.001 L

236 mL = 0.236 L

The final volume of the solution will be 0.236 L.

3 0
3 years ago
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