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3 years ago

1. What amount of ammonia (in moles) is produced by the reaction of 4.00 mol H2 with 3.00 mol Nz?

Chemistry

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

<h2>Answer: 6 moles</h2>

<h3>Explanation:</h3>

3 H₂ + N₂ → 2 NH₃

↓ ↓

4 mol 3 mol

Since the moles of N₂ is the smaller of the two reactants, then N₂ is the limiting factor (the reactant that will decide how much ammonia is produced since it has the smaller amount of moles). ∴ we have to use it in calculating the number of moles of ammonia

The mole ratio of N₂ to NH₃ based on the balanced equation is 1 to 2.

∴ the moles of NH₃ = moles of N₂ × 2

= 3 moles × 2

= 6 moles

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Calculate the percent ionic, the percent covalent, and the bond length (in picometers) of a chemical bond between phosphorus and

kirza4 [7]

Answer:

The correct option is;

4 percent ionic, 96 percent covalent, 222 pm

Explanation:

The parameters given are;

Phosphorus:

Atomic radius = 109 pm

Covalent radius = 106 pm

Ionic radius = 212 pm

Electronegativity of phosphorus = 2.19

Selenium:

Atomic radius = 122 pm

Covalent radius = 116 pm

Ionic radius = 198 pm

Electronegativity of selenium= 2.55

The percentage ionic character of the chemical bond between phosphorus and selenium is given by the relation;

Using Pauling's alternative electronegativity difference method, we have;

$\% \, Ionic \ Character = \left [18\times (\bigtriangleup E.N.)^{1.4} \right ] \%$

Where:

Δ E.N. = Change in electronegativity = 2.55 - 2.19 = 0.36

Therefore;

$\% \, Ionic \ Character = \left [18\times (0.36)^{1.4} \right ] \% = 4.3 \%$

Hence the percentage ionic character = 4.3% ≈ 4%

the percentage covalent character = (100 - 4.3)% = 95.7% ≈ 96%

The bond length for the covalent bond is found adding the covalent radii of both atoms as follows;

The bond length for the covalent bond = 106 pm + 116 pm = 222 pm.

The correct option is therefore, 4 percent ionic, 96 percent covalent, 222 pm.

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3 years ago

A sample of gas has a pressure of 742 torr. What is the pressure in atmospheres?

ycow [4]

Answer:742 torr= approximately 0.976 atm

Explanation:

Since we know that one atm= 760 torr, we can compute the following calculation:

(742 torr/1)*(1atm/760torr)=0.976316 atm

Remember sig figs (3) to round it to 0.976 atm

$\frac{742 torr}{1}$ * $\frac{1 atm}{760 torr}$ =0.976316=0.976 atm

(torr cancels out and we're left with atm)

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