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2 years ago

1. What amount of ammonia (in moles) is produced by the reaction of 4.00 mol H2 with 3.00 mol Nz?

Chemistry

1 answer:

ArbitrLikvidat [17]2 years ago

7 0

<h2>Answer: 6 moles</h2>

<h3>Explanation:</h3>

3 H₂ + N₂ → 2 NH₃

↓ ↓

4 mol 3 mol

Since the moles of N₂ is the smaller of the two reactants, then N₂ is the limiting factor (the reactant that will decide how much ammonia is produced since it has the smaller amount of moles). ∴ we have to use it in calculating the number of moles of ammonia

The mole ratio of N₂ to NH₃ based on the balanced equation is 1 to 2.

∴ the moles of NH₃ = moles of N₂ × 2

= 3 moles × 2

= 6 moles

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¿la densidad de una solución es mayor o menor al agregar agua?

andreev551 [17]

Answer:

La densidad experimenta una disminución

Explanation:

Hola!

En este caso, debemos recordar que la adición de agua incrementa el volumen donde se encuentra un soluto disuelto, el cual posee una cantidad de materia constante. De este modo, sabiendo que la densidad es:

$\rho =\frac{m}{V}$

Al incrementar el denominador (volumen), la densidad experimenta una disminución, al estar en relación inversamente proporcional.

Muchos saludos!

5 0

3 years ago

When the temperature of a gas changes, it's volume decreases from 12 cm3 to 7 cm3 if the final temperature is measured to be 18°

ElenaW [278]

Answer:

The initial temperature is 499 K

Explanation:

Step 1: Data given

initial volume = 12 cm3 = 12 mL

Final volume = 7 cm3 = 7mL

The final temperature = 18 °C = 291 K

Step 2: Calculate the initial temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 0.012 L

⇒with T1 = the initial volume = ?

⇒with V2 = the final volume 0.007 L

⇒with T2 = The final temperature = 291 K

0.012 / T1 = 0.007 / 291

0.012/T1 = 2.4055*10^-5

T1 = 0.012/2.4055*10^-5

T1 = 499 K

The initial temperature is 499 K

8 0

3 years ago

How many centimeters are in .479 kilometers

trapecia [35]

Answer:

47900 cm

General Formulas and Concepts:

<u>Chemistry</u>

Base 10 Decimal System
Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.479 km

<u>Step 2: Identify Conversions</u>

1 km = 1000 m

1 m = 100 cm

<u>Step 3: Convert</u>

<u /> $0.479 \ km(\frac{1000 \ m}{1 \ km} )(\frac{100 \ cm}{1 \ m} )$ = 47900. cm

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

47900. cm ≈ 47900 cm

7 0

3 years ago

A group of students is investigating how the addition of salt impacts the floatation of an egg in water. Four identical cups wer

soldier1979 [14.2K]

Answer: The correct answer is Option 1.

Explanation:

Control group is the group used in the experiment by the researchers in which no change in the variable is done. It is then set as a benchmark for the groups which are being tested.

We are given 4 groups which are being experimented for the flotation of an egg in water. As in Cup 1, there is no addition of salt and hence there is no change in the variables. So, this is set as a benchmark fro the cups which are further used in the experiment conducted.

Hence, the correct answer is Option 1.

4 0

3 years ago

Calculate the number of moles of sulfuric acid in the total volume you used in the lab (i.e., 8.00 mL). Hint: Use the methodolog

insens350 [35]

Answer:

0.147 mol

Explanation:

Step 1: Calculate the volumetric concentration (Cv)

We will use the following expression.

Cv = Cg × ρ

Cv = 98.0 g%g × 1.84 g/mL = 180 g%mL

Step 2: Calculate the molarity of sulfuric acid

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

M = 180 g / 98.08 g/mol × 0.100 L = 18.4 M

Step 3: Calculate the moles of solute in 8.00 mL of solution

8.00 × 10⁻³ L × 18.4 mol/L = 0.147 mol

4 0

2 years ago