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9966 [12]
2 years ago
6

What is the wavelength of a radio wave with a frequency of 2.00 x 10^4 Hz? (hint: what is the speed of all electromagnetic radia

tion?)
ОА
6.67 x 105 m
O
B
1.50 x 104 m
6.00 x 1012 m
6.67 x 10m
Physics
1 answer:
patriot [66]2 years ago
5 0

Answer: Option B

The wavelength for a radio wave with a frequency of  2 × 10⁴ Hz is

1.5 × 10⁴ m.

Explanation:

Wavelength is the measure of distance between two successive crests or troughs in a standing wave. Also wavelength can be measured as the ratio of velocity of light to frequency. It is like this because wavelength is inversely proportional to the frequency.

Wavelength =\frac{c}{frequency}

As c = 3 × 10⁸ m/s and the frequency is 2 × 10⁴ Hz, then the wavelength will be

Wavelength =\frac{3*10^{8} }{2*10^{4} } =1.5*10^{4} m

So, the wavelength for a radio wave with a frequency of  2 × 10⁴ Hz is

1.5 × 10⁴ m.

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Michael has a substance that he puts in Container 1. The substance has a volume of 5 cubic meters. He then puts the substance in
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Gas because liquids and solids volumes don't change from switching containers.
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3 years ago
Astronaut Rob leaves Earth in a spaceship at a speed of 0.960c relative to an observer on Earth. Rob's destination is a star sys
olchik [2.2K]

Answer:

A) 15.0 years

Explanation:

Due to the distance to the star system is in light-year units, we can compute the time by using:

t=\frac{d}{v}=\frac{14.4 l-y}{0.960}=15l-y

then, Rob will take to complete the trip about 15 light-years.

hope this helps!!

7 0
3 years ago
What is the centripetal force
Lelechka [254]

Answer:90N

Explanation:

Mass=30kg

Centripetal acceleration=3m/s^2

centripetal force=mass x centripetal acceleration

Centripetal force=30 x 3

Centripetal force =90

Centripetal force =90N

4 0
3 years ago
A 980 kg roller coaster cart is traveling along a track at 17 m/s before it rolls down a 30 m tall hill (Point A). What will be
MrRissso [65]

The kinetic energy halfway the hill is 2.86\cdot 10^5 J

Explanation:

If there are no friction forces acting on the cart, we can apply the law of conservation of energy: the mechanical energy of the cart (which is the sum of potential energy + kinetic energy) must be conserved. So we can write:

U_A +K_A = U_B + K_B

where

U_A=mgh_A is the initial potential energy, at point A, with

m = 980 kg (mass of the cart)

g=9.8 m/s^2 (acceleration of gravity)

h_A = 30 m (height at point A)

K_A=\frac{1}{2}mv_A^2 is the initial kinetic energy, at point A , with

v_A=17 m/s (velocity at point A)

U_B=mgh_B is the final potential energy, at point B, where

h_B = 15 m (height at point B)

K_B=\frac{1}{2}mv_B^2 is the final kinetic energy, at point B, where

v_B is the velocity at point B

Here we are interested in finding K_B, so by re-arranging the equation and substituting we find:

K_B = U_A+K_B-U_B = mg(h_A-h_B)+\frac{1}{2}mv_A^2=(980)(9.8)(30-15)+\frac{1}{2}(980)(17)^2=2.86\cdot 10^5 J

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

8 0
3 years ago
A block lies on a frictionless floor. a force of 5 n pulls toward the east while a force of 4 n pulls toward the north. what is
sveticcg [70]

Given below the arrangement of loading on the larger boat by two tug boats.

F₁ = 5 N

F₂ = 4 N

Angle between them θ = 90⁰

Resultant between two vectors, F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\theta }

Substituting

   F = \sqrt{5^2+4^2+2*5*4*cos 90} \\ \\ = 6.403 N

So magnitude of the net force on the block = 6.403 N

3 0
3 years ago
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