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Ket [755]
3 years ago
15

What are the ropes of secretaries and treasures in a meeting​

Engineering
1 answer:
Nastasia [14]3 years ago
4 0

Answer:

To prepare and issue notices and agendas of all meetings in consultation with the chairman, and to ensure that any background papers are available well before the meeting. To attend and take the minutes of every committee meeting. To circulate minutes to all committee members, and to conduct the correspondence

Explanation:

I think you want to say roles.

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Railroad tracks made of 1025 steel are to be laid during the time of year when the temperature averages 4C (40F). Of a joint spa
DENIUS [597]

Answer:

41.5° C

Explanation:

Given data :

1025 steel

Temperature = 4°C

allowed joint space = 5.4 mm

length of rails = 11.9 m

<u>Determine the highest possible temperature </u>

coefficient of thermal expansion ( ∝ ) = 12.1 * 10^-6 /°C

Applying thermal strain ( Δl / l )  = ∝ * ΔT

                                    ( 5.4 * 10^-3 / 11.9 )  = 12.1 * 10^-6 * ( T2 - 4 )

∴  ( T2 - 4 ) =  ( 5.4 * 10^-3 / 11.9 ) / 12.1 * 10^-6

hence : T2 = 41.5°C

8 0
3 years ago
During January, at a location in Alaska winds at -20°C can be observed, However, several meters below ground the temperature rem
maw [93]

Answer:

a) \eta_{th} = 10.910\,\%, b) Yes.

Explanation:

a) The maximum thermal efficiency is given by the Carnot's Cycle, whose formula is:

\eta_{th} =\left(1-\frac{253.15\,K}{284.15\,K}  \right) \times 100\,\%

\eta_{th} = 10.910\,\%

b) The claim of the inventor is possible since real efficiency is lower than maximum thermal efficiency.

4 0
4 years ago
The article provides information by using a list. What does it list? A. Thanksgiving food B. places where clams can be found C.
Gelneren [198K]

Answer:

C

Explanation:

7 0
3 years ago
6. Find the heat flow in 24 hours through a refrigerator door 30.0" x 58.0" insulated with cellulose fiber 2.0" thick. The tempe
Ilia_Sergeevich [38]

Answer:

The heat flow in 24 hours through the refrigerator door is approximately 1,608.57 BTU

Explanation:

The given parameters are;

The duration of the heat transfer, t = 24 hours = 86,400 seconds

The area of the refrigerator door, A = 30.0" × 58.0" = 1,740 in.² = 1.122578 m²

The material of the insulator in the door = Cellulose fiber

The thickness of the insulator in the door, d = 2.0" = 0.0508 m

The temperature inside the fridge = 38° F = 276.4833 K

The temperature of the room = 78°F = 298.7056 K

The thermal conductivity of cellulose fiber = 0.040 W/(m·K)

By Fourier's law, the heat flow through a by conduction material is given by the following formula;

\dfrac{Q}{t} = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d}

Q = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d} \times t

Therefore, we have;

Q = \dfrac{0.04 \times 1.122578 \times (298.7056 - 276.4833 ) }{0.0508} \times 86,400 =1,697,131.73522

The heat flow in 24 hours through the refrigerator door, Q = 1,697,131.73522 J = 1,608.5705140685 BTU

7 0
3 years ago
In an air standard diesel cycle compression starts at 100kpa and 300k. the compression ratio is 16 to 1. The maximum cycle tempe
KIM [24]

Answer:

\eta=0.60

Explanation:

Given :Take \gamma=1.4 for air

      P_1=100 KPa  ,T_1=300K

  \frac{V_1}{V_2}=r ⇒ r=16

As we know that  

   T_2=T_1(r^{\gamma-1})

So T_2=300\times 16^{\gamma-1}

  T_2=909.42K

Now find the cut off ration \rho

      \rho=\frac{V_3}{V_2}  

         \frac{V_3}{V_2}=\frac{T_3}{T_2}

\rho=\frac{2031}{909.42}

 \rho=2.23

So efficiency of diesel engine

\eta =1-\dfrac{\rho^\gamma-1}{\gamma\times r^{\gamma-1}(\rho-1)}

Now by putting the all values

\eta =1-\dfrac{2.23^{1.4}-1}{1.4\times 16^{1.4-1}(2.23-1)}

So \eta=0.60

So the efficiency of diesel engine=0.60

     

7 0
3 years ago
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