All categories

2 years ago

TILEF

Chemistry

1 answer:

torisob [31]2 years ago

7 0

Answer:

Explanation:

sodium has mass number 23 and atomic number 11 so number of protons =number of electrons =atomic number which is 11 and number of neutrons=mass number-number of protons =23-11=12

You might be interested in

You have lost nearly 6 inches of top soil on your 200 acre field in the last 10 years. The problem seems to be getting even wors

qaws [65]

You could consider building an irrigation system.

6 0

3 years ago

4. If they..................me a question d have answered it.(ask/asked/had asked)

LekaFEV [45]

Answer:

had asked

Explanation:

If they had asked me a question, I would have answered it.

5 0

2 years ago

Read 2 more answers

I need help with the question please help

Irina18 [472]

Answer:

Explanation:

u are right

8 0

2 years ago

Read 2 more answers

An objects tendency to maintain its current state of motion is called

daser333 [38]

Inertia is the tendency of an object to remain at rest or remain in motion. Inertia is related to an object's mass.

3 0

2 years ago

A 51.24-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 liters of solution. How many mL of this solution must be d

g100num [7]

Answer:

0.40 L

Explanation:

Calculation of the moles of $Ba(OH)_2$ as:-

Mass = 51.24 g

Molar mass of $Ba(OH)_2$ = 171.34 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{51.24\ g}{171.34\ g/mol}$

$Moles= 0.2991\ mol$

Volume = 1.20 L

The expression for the molarity is:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity=\frac{0.2991\ mol}{1.20\ L}=0.24925\ M$

Thus,

Considering

$Molarity_{working\ solution}\times Volume_{working\ solution}=Molarity_{stock\ solution}\times Volume_{stock\ solution}$

Given that:

$Molarity_{working\ solution}=0.100\ M$

$Volume_{working\ solution}=1\ L$

$Volume_{stock\ solution}=?$

$Molarity_{stock\ solution}=0.24925\ M$

So,

$0.100\ M\times 1\ L=0.24925\ M\times Volume_{stock\ solution}$

$Volume_{stock\ solution}=\frac{0.100\times 1}{0.24925}\ L=0.40\ L$

<u>The volume of 0.24925M stock solution added = 0.40 L </u>

6 0

2 years ago