<span>c. q = 0.75 g x 0.897 j/g•°c x 22°c</span>
Answer:
Cp = 5.982 R
∴ R: ideal gas constant
Explanation:
expand reversibly and adiabatically:
∴ T1 = 298.15 K
∴ T2 = 248.44 K
∴ P1 = 1522.2 Torr
∴ P2 = 613.85 Torr
⇒ δU = δQ + δW......first law
∴ Q = 0....adiabatically
⇒ δU = CvδT = δW = - PδV
⇒ CvδT = - nRT/V δV
⇒ CvδT/nT = - R δV/V
∴ Cv/n = Cv,m
⇒ Cv,m Ln(T2/T1) = R Ln(V1/V2)
⇒ Cv,m ( - 0.1823 ) = R ( - 0.9082 )
⇒ Cv.m = 4.982 R
∴ Cp,m - Cv,m = R...."perfect" gas
⇒ Cp,m = R + Cv,m
⇒ Cp,m = R + 4.982 R
⇒ Cp,m = 5.982 R
∴ Cp,m = Cp/n
assuming: n = 1 mol fluorocarbon gas
⇒ Cp = 5.982 R
∴ R: ideal gas constant
Hello!
The percent yield of the combustion of Nitrogen Oxide in the plant is
65,22%The chemical equation for the reaction is:
2NO + O₂ → 2NO₂
To calculate the percent yield we need to calculate the theoretical yield, using the following conversion factor:
![1500 kg NO* \frac{1000 g NO}{1 kg NO}* \frac{1 mol NO}{30 g NO}* \frac{2 mol NO_2}{2 mol NO}* \frac{46 g NO_2}{1 mol NO_2}* \frac{1 kg}{1000 g} \\ \\ = 2300 kg NO_2](https://tex.z-dn.net/?f=1500%20kg%20NO%2A%20%5Cfrac%7B1000%20g%20NO%7D%7B1%20kg%20NO%7D%2A%20%5Cfrac%7B1%20mol%20NO%7D%7B30%20g%20NO%7D%2A%20%5Cfrac%7B2%20mol%20NO_2%7D%7B2%20mol%20NO%7D%2A%20%5Cfrac%7B46%20g%20NO_2%7D%7B1%20mol%20NO_2%7D%2A%20%5Cfrac%7B1%20kg%7D%7B1000%20g%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%202300%20kg%20NO_2%20%20)
Now we use the following equation to calculate the percent yield:
![\% yield= \frac{Actual Yield}{Theoretical Yield}*100= \frac{1500 kg}{2300 kg}*100=65,22 \%](https://tex.z-dn.net/?f=%5C%25%20yield%3D%20%5Cfrac%7BActual%20Yield%7D%7BTheoretical%20Yield%7D%2A100%3D%20%20%5Cfrac%7B1500%20kg%7D%7B2300%20kg%7D%2A100%3D65%2C22%20%5C%25%20)
Have a nice day!
Answer:
Chlorine --> 89%
Explanation:
Step 1) Add each element's amu up to get the total mass of the compound.
12.011+1.008+3(35.453) = 119.378.
Step 2) Divide the total mass of chlorine by the total mass of the compound.
3(35.453) = 106.359
106.359/119.378 = 0.8909430548.
Step 3) Now multiply by 100 to get the percentage.
0.8909430548*100 = 89.09430548%
Step 4) Estimate and submit your answer
89.09430548% estimates to 89%