Speed of the roller coaster at the top of the loop= 7.67 m/s
Explanation:
using the law of conservation of energy
KEi + PEi= KEf + PEf
KEi= kinetic energy at the top of the hill=0 because the car is at rest there.
PEi= potential energy at the top of the hill
PEf= potential energy at the top of the loop
KEf= kinetic energy at the top of the loop
Also kinetic energy= 1/ 2m v² and potential energy= mgh
m= mass
h= height
v= velocity
so 0+ mghi = 1/2mv² + mg h
500 (9.8)(10)+ 1/2 (500) v²= 500 ( 9.8) (7)
49000+250 v²= 34300
250v²= 14700
v²=58.8
v=7.67 m/s
Answer:
Explanation:
given ;
- coefficient of kinetic friction = 0.80
- considering the force acting in horizontal direction and from newton's 2nd law of motion;
- for vertical motion = Fn - mg = 0
- for horizontal motion = F = ma + miu mg = m( a + miu.g)
- therefore, F = miu mg where g = 9.81m/s^2
- plugging the values into the equation;
Horizontal force = 204.05N
Answer:
first option bro
Explanation:
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Answer:
Distance, S = 130m
Explanation:
Given the following data;
Initial velocity = 2m/s
Final velocity = 28m/s
Acceleration = 3m/s²
To find the distance, we would use the third equation of motion.
V² = U² + 2aS
Substituting into the equation, we have;
28² = 2² + 2*3*S
784 = 4 + 6S
6S = 784 - 4
6S = 780
S = 780/6
Distance, S = 130m
Answer:
Gamma rays is the correct answer.
Explanation:
