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Ratling [72]
3 years ago
6

PLease help me WIll give brainliest

Physics
1 answer:
melisa1 [442]3 years ago
3 0

Answer:

6

Explanation:

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Which type of rays have a wavelength shorter than that of visible light?
aniked [119]

Answer:

c

Explanation:

wavelength shorter means energy is higher

the wavelength

radio waves>microwave>infrared rays>gamma rays

6 0
2 years ago
A 3 Ω resistor, an 8 Ω resistor, and a 14 Ω resistor are connected in parallel across a 6 V battery. Determine the equivalent re
Schach [20]

Answer:

R=25Ω

Explanation:

Given data:

R1=3 Ω

R2=8 Ω

R3=14 Ω

V=6

Now,

To Find,

R=?

Formula

R=R1+R2+R3

put the values,

R=3+8+14

R=25Ω

6 0
3 years ago
*WILL MARK BRAINLIEST FOR RIGHT ANSWER* How much current must be applied across a 60 Ω light bulb filament in order for it to co
sp2606 [1]

Answer: The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

Explanation:

You can find the current in amperes using ohms and watts from this formula:

I = \sqrt{\frac{P}{R} }

Where P represents power in watts, R represents resistance in ohms, and I represents current in amperes.

You can then substitute 60 and 55 into the equation to find I:

I = \sqrt{\frac{55}{60} } \\I = \frac{\sqrt{55} }{\sqrt{60} }

Then, simplify the denominator:

I = \frac{\sqrt{55} }{2\sqrt{15} }

Rationalize the denominator:

I = \frac{\sqrt{55} }{2\sqrt{15} } * \frac{\sqrt{15} }{\sqrt{15} } = \frac{\sqrt{825} }{30}

Simplify the numerator by finding its factors:

I = \frac{5\sqrt{33} }{30} = \frac{\sqrt{33} }{6}

The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

8 0
3 years ago
How was dyslexia treated in the past and how is dyslexia treated today?
TiliK225 [7]
Dyslexia is treated using specific educational approaches and techniques, and the sooner the intervention begins, the better.
4 0
3 years ago
Como un astronauta utiliza la fuerza de hallar y empujar?
PilotLPTM [1.2K]

Answer:

La única manera en que nuestro astronauta sería capaz de empujar la nave espacial en el espacio sin alejarse sería usar algo llamado "unidad de propulsión de astronauta". Supongamos que el astronauta está usando un SPK soviético, el sistema de cohetes mochila más poderoso jamás utilizado en el espacio.

Explanation:

3 0
3 years ago
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