All categories

3 years ago

In operant conditioning, generalization occurs when

1 answer:

5 0

Typically occurs when we associate things to other things that look alike. We see that in many experiments, specifically “Little Albert” who was conditioned to be afraid of rats but later was afraid of anything that resembled that of a rat.
Hope this helps!

You might be interested in

A balloon filled with helium has a small hole on the right side of the balloon. How would Pascal explain why the entire balloon

Morgarella [4.7K]

Answer:

delete this answer please.

4 0

3 years ago

What is the kinetic energy of a 0.135 kg baseball thrown at 40 m/s

Ronch [10]

KE = 1/2 * m * v^2
KE = 1/2 * 0.135 * 40^2
KE = 1/2 * 0.135 * 1600
KE = 108 J

4 0

3 years ago

Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.1 g. Silver has 47 electrons

Assoli18 [71]

<u>Answer:</u> The number of electrons in given amount of silver are $1.87\times 10^{24}$

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of silver = 7.1 g

Molar mass of silver = 107.87 g/mol

Putting values in above equation, we get:

$\text{Moles of silver}=\frac{7.1g}{107.87g/mol}=0.066mol$

Number of electrons in 1 atom of silver = 47

According to mole concept:

1 mole of an element contains $6.022\times 10^{23}$ number of particles

So, 0.066 moles of silver will contain = - $(0.066\times 47\times 6.022\times 10^{23})=1.87\times 10^{24}$ number of electrons

Hence, the number of electrons in given amount of silver are $1.87\times 10^{24}$

7 0

3 years ago

A sound has a sound level of 30 dB. Its intensity is what multiple of the standard reference level for intensities?

arsen [322]

<h2>Answer:</h2>

1000th multiple of the standard reference level for intensities.

<h2>Explanation:</h2>

The sound intensity level (β), measured in decibels, of a sound with an intensity of I is defined as follows;

β = 10 log (I / I₀) --------------------(i)

Where;

I₀ = reference intensity

Given from the question;

β = sound level = 30dB

Substitute this value into equation (i) as follows;

30 = 10 log (I / I₀)

Divide both sides by 3;

3 = log (I / I₀)

Take antilog of both sides;

10^(3) = (I / I₀)

1000 = I / I₀

Solve for I;

I = 1000I₀

Therefore the intensity of the sound is 1000 times the standard reference level for intensities (I₀)

7 0

3 years ago

Helpp me pleassee....

lilavasa [31]

Answer:

The fundamental wavelength of the vibrating string is 1.7 m.

Explanation:

We have,

Velocity of wave on a guitar string is 344 m/s

Length of the guitar string is 85 cm or 0.85 m

It is required to find the fundamental wavelength of the vibrating string. The fundamental frequency on the string is given by :

$f=\dfrac{v}{2l}\\\\f=\dfrac{344}{2\times 0.85}\\\\f=202.35\ Hz$

Now fundamental wavelength is :

$\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{344}{202.35}\\\\\lambda=1.7\ m$

So, the fundamental wavelength of the vibrating string is 1.7 m.

4 0

3 years ago