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garri49 [273]
2 years ago
5

How many atoms of zinc are required to weigh 5.4 ng

Chemistry
1 answer:
Gwar [14]2 years ago
6 0

Answer:

4.97 X 10^13 ATOMS OF Zn

Explanation:

how many atoms of zinc are required to weigh 5.4 ng

a nano gram is 10^-9 grams

Zinc has an atomic mass of 65.39 gm/moles

there is an Avogadros number of atoms in a mole

65.39 GRAMS PER MOLE

65.39 g/(6.022 X 10^23)how many atoms of zinc are required to weigh 5.4 ng

 GRAMS PER ATOM

1.086 GRAMS PER  1O^22 ATOMS

1 atom of Zn weighs 1.086 X 10^9 X 1O^-22 n grm=

1,086 X 10^-13 n gm                              

Y tines 1.086 X 10^-13 = 5.4 n gm

Y = 5.4/ (1.086 X 10^-13) =

4.97 X 10^13 ATOMS OF Zn

CHECK

(4.97 X 10^13 ) X 65.39 gm/(6.022 X 10^23) =

5.397 X 10^-9 =

5.4 n g

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