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3 years ago

Why Leaves Change Color in the Fall?

Physics

1 answer:

inna [77]3 years ago

8 0

Answer:

During the fall the day gets shorter hence less sunlight this results to leaves stopping their food making process. The chlorophyll breaks down, the green color disappears and the yellow to orange color becomes visible

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Please help..................

worty [1.4K]

Answer:

PART A

In a solid

The attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.

In a liquid

Particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

A gas

The particles move rapidly in all directions, frequently colliding with each other and the side of the container. With an increase in temperature, the particles gain kinetic energy and move faster.

PART B

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.

Explanation:

GOOD LUCK!!! :)

7 0

3 years ago

A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How man

iVinArrow [24]

Answer:

Explanation:

30 rev/min (2π rad/rev) / (60 s/min) = π rad/s

α = Δω/t = (0 - π)/3 = π/3 rad/s²

θ = ½αt² = ½(π/3)3² = 1.5π radians

θ = 1.5π rad/2π rad/rev = 0.75 rev

8 0

3 years ago

What is the density of lead (in g/cm3) if a rectangular bar measuring 0.50 cm in height, 1.55 cm in width, and 25.00 cm in lengt

Otrada [13]

If you look at the units of density, g/cm^3 you will see it's grams divided by volume (cm^3).

218.9 g / (0.5*1.55*25 cm^3) = 11.3 g/cm^3

4 0

4 years ago

Read 2 more answers

I WILL GIVE BRAINLIEST IF SOMEONE GETS THIS......

pav-90 [236]

Answer:

Explanation:

Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.

100 $cm^{2}$ x 10cm = 1000 $cm^{3}$

Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....

$\frac{1g}{cm^{3} }$ x 1000 $cm^{3}$ = 1000g or 1kg

Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....

1000g + 100g = 1100g or 1.1kg

The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....

20g ÷ $\frac{8g}{cm^{3} }$ = 2.5 $cm^{3}$

Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5 $cm^{3}$ overflowed. So now we the same process as in number a) just with a few adjustments.

$\frac{1g}{cm^{3} }$ x (1000 $cm^{3}$ - 2.5 $cm^{3}$ ) = 997.5g

So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.

100g + 997.5g + 20g = 1117.5g or 1.1175kg

5 0

3 years ago

What happens to ocean water as it moves from Antarctica to the equator

Charra [1.4K]

As they move water, ocean currents distribute heat and nutrients around the globe.

5 0

4 years ago