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Kruka [31]
3 years ago
10

Ya'lll better answer my question rightnow

Physics
2 answers:
Viefleur [7K]3 years ago
8 0
H e l l o I’m answering teehe how r u
lilavasa [31]3 years ago
5 0

Answer: ok

Explanation:

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A large piece of jewelry has a mass of 132.6 g. a graduated cylinder initially contains 48.6 ml water. when the jewelry is subme
Lerok [7]

The density of the substance is<u> 10.5 g/cm³.</u>

The jewelry is made out of <u>Silver.</u>

Density ρ is defined as the ratio of mass <em>m</em> of the substance to its volume V<em>. </em> The cylinder contains a volume <em>V₁ of water</em> and when the jewelry is immersed in it, the total volume of water and the jewelry is found to be V₂.

The volume <em>V</em> of the jewelry is given by,

V=V_2 -V_1

Substitute 48.6 ml for <em>V₁ </em>and 61.2 ml for V₂.

V=V_2 -V_1\\ =61.2 ml -48.6 ml\\ =12.6 ml

calculate the density ρ of the jewelry using the expression,

\rho =\frac{m}{V}

Substitute 132.6 g for <em>m</em> and 12.6 ml for <em>V</em>.

\rho =\frac{m}{V}\\ =\frac{132.6 g}{12.6 ml} \\ =10.5 g/ml

Since 1 ml=1 cm^3,

The density of the jewelry is <u> 10.5 g/cm³.</u>

From standard tables, it can be seen that the substance used to make the jewelry is <u>silver</u><em><u>, </u></em>which has a density 10.5 g/cm³.



4 0
3 years ago
A rocket is launched from rest and moves in a straight line at 30.0 degrees above the horizontal with an acceleration of 35.0 m/
klemol [59]

Answer:

t = 123.59s

Explanation:

For the launch pad section:

Vf = Vo + a*t  where Vo=0.

Vf = 35*25 = 875m/s

The distance traveled during the launch:

d = Vo*t+\frac{a*t^2}{2} = 0+\frac{35*25^2}{2} = 10937.5m

Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.

\Delta Y = Vo*sin(30)*t - \frac{g*t^2}{2}

-d*sin(30) = Vo*sin(30)*t - \frac{g*t^2}{2}  where d= 10937.5m; Vo=875m/s.

Solving for t:

t1 = -11.093s   t2 = 98.59s

So, the total time of flight will be:

t_{total} = t_{launch}+t_{projectile}=25+98.59 = 123.59s

6 0
3 years ago
A circular coil of radius 5.0 cm and resistance 0.20 Ω is placed in a uniform magnetic field perpendicular to the plane of the c
DedPeter [7]

Answer:

The induced current in the coil at the time 2 s is 0.00263 A

Explanation:

The equation for induced emf is equal to:

\epsilon =-\frac{d}{dt} (BAcos\theta )

Where

B = magnetic field

A = area

θ = angle

\epsilon =-Acos0\frac{d}{dt} B\\\epsilon =-(\pi r^{2} )\frac{d}{dt} (0.5e^{-0.2t} )\\\epsilon =0.1 (\pi r^{2} )e^{-0.2t}

For t = 2 s

\epsilon =0.1*\pi *0.05^{2} *e^{-0.2*2} =5.26x10^{-4} V

The induced current is:

I=\frac{\epsilo }{R} =\frac{5.26x10^{-4} }{0.2} =0.00263A

3 0
3 years ago
If the number of homes with a pet dog is equal to 250, how many total homes are repersented by the chart?
scoray [572]
500 because 250 x 2 = 500
3 0
4 years ago
Two forces are acting on an object as shown in Fig. on the right. What is the magnitude of the resultant force?
svetlana [45]

Answer:

185 N

Explanation:

Sum of forces in the x direction:

Fₓ = -(80 N cos 75°) + (120 N cos 60°)

Fₓ = 39.3 N

Sum of forces in the y direction:

Fᵧ = (80 N sin 75°) + (120 N sin 60°)

Fᵧ = 181.2 N

The magnitude of the net force is:

F = √(Fₓ² + Fᵧ²)

F = √((39.3 N)² + (181.2 N)²)

F = 185 N

8 0
3 years ago
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