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antoniya [11.8K]
3 years ago
5

A 35 g steel ball is held by a ceiling-mounted electromagnet 3.5 m above the floor. A compressed-air cannon sits on the floor, 4

.0 m to one side of the point directly under the ball. When a button is pressed, the ball drops and, simultaneously, the cannon fires a 25 g plastic ball. The two balls collide 1.0 m above the floor. What was the launch speed of the plastic ball
Physics
1 answer:
iren [92.7K]3 years ago
3 0

Answer:

8.95 m/s

Explanation:

(3.5-1.0) x 2 = gt²

t = √5/9.8 = 0.714 sec  

V_x = X/t = 4/ 0.714 = 5.602 m/s

vertical velocity means it has to rise 1.0 m against gravity in 0.714s

V_o_y = gt = 9.8 x 0.714 = 6.99 m/s

V = √V_o_y²+V_x ² = √6.99²+5.602² = 8.95 m/s

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