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Ostrovityanka [42]
2 years ago
6

What fraction of the original atoms of the radioactive sample will remain after the given number of half-lives has passed?

Chemistry
1 answer:
meriva2 years ago
5 0

Answer:

1/8

Explanation:

\frac{1}{ {2}^{3} }  =  \frac{1}{8}

Mark brainliest please

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Help on question 1b please? (image attached)
aliya0001 [1]
I believe your answer Is C. An ammonia molecule has a trigonometrical pyramidal shape. Figure C has a <span>has a trigonometrical pyramidal shape.</span>

I hope I help
3 0
3 years ago
Consider the Fischer ester synthesis of methyl benzoate from benzoic acid and methanol in the presence of sulfuric acid as a cat
zlopas [31]

Answer:

48.8%

Explanation:

The reaction has a 1:1 mole ratio so;

Number of moles of benzoic acid reacted = mass/molar mass = 3.8 g/122.12 g/mol = 0.03 moles

So;

0.03 moles of methyl benzoate is formed in the reaction

Mass of methyl benzoate formed = 0.03 moles * 136.15 g/mol = 4.1 g

percent yield = actual yield/theoretical yield * 100/1

percent yield = 2.0 g/4.1 g * 100 = 48.8%

4 0
3 years ago
How many moles of ions are there in 3 moles of calcium chloride?
klemol [59]

Answer:

9 moles of ions

Explanation:

Our compound is: CaCl₂(s)

We dissociate it:

CaCl₂(aq) → Ca²⁺ (aq) + 2Cl⁻(aq)

Per 1 mol of chloride, we have 1 mol of calcium cation and 2moles of chlorides, so in total we have 3 moles of ions.

Therefore in 3 moles of chloride, we would have 9 moles of ions (3 . 3)

5 0
3 years ago
Hi guys, my question is:
guapka [62]

Answer:

See Explanation Below

Explanation:

A) The rate law can only be on the reactant side and you can only determine it after you get the net ionic equation because of spectators cancelling out. So in this case the rate law is k=[CH3Br]^1 [OH-]^1. The powers are there because the rxn is first order.  

B) Since the rxn is first order anything you do to it will be the exact same "counter rxn" per say so since you are decreasing the OH- by 5 the rate will decease by 5

C) The rate will increase by 4 since you are doubling both you have to multiply them both.

8 0
3 years ago
what is the best course of action if solid material remains in the flask after the heating step of recrystallization
lys-0071 [83]

Answer:

filter the hot mixture.

Explanation:

Solid is stayed undissolved since the arrangement is gotten super saturated. On the off chance that solid molecule is available recrysallization won't happen in this way we need expel the solid molecule by filtarion in hot condition itself . Subsequently, arrangement become totally homogenous and recrysallization item will shaped by moderate cooling

7 0
3 years ago
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