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Ostrovityanka [42]
2 years ago
6

What fraction of the original atoms of the radioactive sample will remain after the given number of half-lives has passed?

Chemistry
1 answer:
meriva2 years ago
5 0

Answer:

1/8

Explanation:

\frac{1}{ {2}^{3} }  =  \frac{1}{8}

Mark brainliest please

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100POINTS!!!!<br><br> Label each reaction to either homogeneous OR heterogeneous
liraira [26]
First is homogeneous and so is the third. second is heterogeneous
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2 years ago
What would be the greatest difference in using an open ceramic coffee mug rather than an insulated mug with a lid as a calorimet
STALIN [3.7K]

Answer:

Hi. Increased evaporation would be the greatest difference.

Explanation:

Have you ever had a drink in a mug with a lid? When you would remove the lid, all of the liquid on the lid is the liquid that would evaporate if there was no lid.

6 0
3 years ago
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Tierra is playing in her backyard when she hears her friend calling out to her. She can't see her friend but can hear her friend
mixer [17]

Answer:

diffraction

Explanation:

the correct answer is diffraction

4 0
3 years ago
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What is the name of this alkane? two central carbons are bonded to c h 3 at each end, h below, and c h3 above the left carbon an
Kazeer [188]

The name of this alkane is with central carbons are bonded to c h 3 is 2-methylbutane.

<h3>What is alkane?</h3>

Alkanes belong to the family of  saturated hydrocarbons with carbon carbon single bond.

For the given alkane;

          CH₃    H

 CH₃ -  C   -  C - CH₃

            H      H

Thus, the name of this alkane is with central carbons are bonded to c h 3 is 2-methylbutane.

Learn more about alkane here: brainly.com/question/24270289

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4 0
2 years ago
An experiment reveals that 125.0 grams of an unknown metal increases in temperature from 22.0 oC to 43.6 oC upon absorbing 640 j
nydimaria [60]

Answer:

                     Cp  =  0.237 J.g⁻¹.°C⁻¹

Explanation:

                      Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                 Q  =  m Cp ΔT   ----- (1)

Where;

           Q  =  Heat  =  640 J

           m  =  mass  =  125 g

           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

Solving eq. 1 for Cp,

                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

3 0
3 years ago
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