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3 years ago

There are no risks when taking medication to treat anxiety.

Physics

2 answers:

egoroff_w [7]3 years ago

8 0

Answer:

The answer is False

Explanation:

lidiya [134]3 years ago

5 0

Answer:

False

Explanation:

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Electric current is the flow of charged particles called blank .

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The electric current is measured in coulombs per second. A flow of one coulomb per second is called one ampere

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Visible light waves do not diffract as well as radio waves because?

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They have more energy than radio waves.

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As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr

Nitella [24]

Answer:

1. Part A: 648N
2. Part B: 324J
3. Part C: 1,296N

Explanation:

1. Part A:

The magnitude of the force is calculated using the Hook's law:

$|F|=k\Delta x$

You know $\Delta x=0.250m$ but you do not have $k$ .

You can calculate it using the equation for the work-energy for a spring.

The work done to compress the springs a distance $\Delta x$ is:

$Work=\Delta PE=(1/2)k(\Delta x)^2$

Where $\Delta PE$ is the change in the elastic potential energy of the "spring".

Here you have two springs, but you can work as if they were one spring.

You know the work (81.0J) and the length the "spring" was compressed (0.250m). Thus, just substitute and solve for k:

$81.0J=(1/2)k(0.250m)^2\\\\k=2,592N/m$

In reallity, the constant of each spring is half of that, but it is not relevant for the calculations and you are safe by assuming that it is just one spring with that constant.

Now calculate the magnitude of the force:

$|F|=k\Delta x=2,592N/m\times 0.250m=648N$

2. Part B. How much additional work must you do to move the platform a distance 0.250 m farther?

The additional work will be the extra elastic potential energy that the springs earn.

You already know the elastic potential energy when Δx = 0.250m; now you must calculate the elastic potential energy when Δx = 0.250m + 0.250m = 0.500m.

$\Delta E=(1/2)2,592n/m\times(0.500m)^2=324J$

Therefore, you must do 324J of additional work to move the plattarform a distance 0.250 m farther.

3. Part C

What maximum force must you apply to move the platform to the position in Part B?

The maximum force is when the springs are compressed the maximum and that is 0.500m

Therefore, use Hook's law again, but now the compression length is Δx = 0.500m

$|F|=k\Delta x=2,592N/m\times 0.500m =1,296N$

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3 years ago

During a rainstorm, water seeps into the ground. This process is called _____.

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During a rainstorm, water seeps into the ground. This process is called INFILTRATION.

Infiltration is a part of the six process of the water cycle. It is the second part of the cycle.

The 6 processes are CONDENSATION, INFILTRATION, RUNOFF, EVAPORATION, PRECIPITATION, TRANSPIRATION.

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Please need help on this

kirill115 [55]

The frequency cannot change, as it depends on the source. now, imagine light as a particle, when it's going through glass, which is a denser medium than air, is more tightly packed with particles than air is. think of it this way, will you walk faster in a crowd or on an empty street? going through the empty street (air) there are lesser objects to bump into so what do you think will happen to the speed now?

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