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elixir [45]
3 years ago
5

Please help me guys please​

Physics
1 answer:
leonid [27]3 years ago
8 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Solution is in attachment ~

I hope that you got what you were looking for, and if there's different data then go through the same procedure, using same formula with different values and you will get your answer ~

\mathrm{✌TeeNForeveR✌}

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The weight of a girl on the Earth is 340 N, what is her mass on Earth?(g= 10Nkg-1)​
kirill [66]

Answer:

34 kg is the answer to the question

4 0
3 years ago
3. You drop an egg out of your 10 m 2nd story window. If it took 1.43 sec, calculate the
zhannawk [14.2K]

Answer:

15 is the answer

Explanation:

i multiplied 1.5 by 10 to get 15

8 0
4 years ago
In an extrasolar planetary system containing a single planet, the parent star is measured to move about its center of mass every
Mademuasel [1]

Answer:

Orbital Time Period is 24 years

Explanation:

This can be explained by the definition of time period.

Time period can be defined as the time taken by an object to complete one cycle, here, time taken to complete one revolution.

Also, we know that an extra solar planet which is also called as an exo planet is that planet which is outside our solar system and orbits any star other than our sun. The system in consideration is extra solar system with a single planet.

Therefore, the time taken by the parent star to move about its mass center is the orbital time period that is 24 years.

4 0
3 years ago
The capacitance of the variable capacitor of a radio can be changed from 100 to 350 pF by turning the dial from 0° to 180°. With
tangare [24]

Answer:

0.7 mJ

Explanation:

<u>Identify the unknown:  </u>

The work required to turn the dial from 180° to 0°  

<u>List the Knowns:  </u>

Capacitance when the dial is set at 180°: C = 350 pF = 350 x 10^-12 F Capacitance when the dial is set at 0°: C = 100 pF = 100 x 10^-12 F  

Voltage of the battery: V = 130 V  

<u>Set Up the Problem:</u>  

<em><u>Energy stored in a capacitor: </u></em>

U_c=1/2*V^2*C

      =1/2*Q^2/C

<em><u>When the dial is set at 180°:</u></em><em>  </em>

U_c=1/2*(130)^2*350*10^-12=10^-4

Q=√2*U_c*C=4*10^-7

<u><em>When the dial is set at 0°:</em></u>  

U_c=1/2*(4*10^-7)^2/100*10^-12

      =8*10^-4 J

<u><em>Solve the Problem:  </em></u>

ΔU_c=7*10^-4 J

        =0.7 mJ

note:

there maybe error in calculation but method is correct

4 0
3 years ago
Read 2 more answers
What is responsible for the apparent motion of the Moon in the sky from East to West?
DiKsa [7]

As a result, although the Moon is moving to the east relative to the stars, the much faster westward motion of the sky is carrying it to the west, so despite its eastward motion relative to the center of the Earth, it rises in the east and sets in the west, just like any other celestial body.


6 0
4 years ago
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