Answer:
(a) 25 m
(b) 75 m
Explanation:
Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.
So, the speed of the jogger,

Let d be the distance covered by him in time, t s.
As distance=(speed) x (time)
So, 
From equation (i)

As the jogger starts from origin, so, the distance,
, also represents the position of the jogger at the time
s.
The position-time graph has been shown.
(a) From equation (ii), for t=5.0 s

So, the jogger is at a distance of 25 m from the origin.
(b) Similarly, for t=15.0 s

So, the jogger is at a distance of 75 m from the origin.