Bae what are the options i took this test back in 7th id remember if i saw em
<h3>Answer: any path that allows electrons to flow</h3>
An electrical circuit is a path in which electrons from a voltage or current source flow. ... The part of an electrical circuit that is between the electrons' starting point and the point where they return to the source is called an electrical circuit's "load".
Biotic components are living things. The root word bio means life. When you say something is abiotic, it means non-living things. The prefix "a" means not or non.
<span>Sunlight and heat: Abiotic
Insects: Biotic
Rotting log: Biotic (This is considered biotic because it was a living thing.)
Bacteria: Biotic
Water: Abiotic
Rocks: Abiotic</span>
A mixture is a combination of two or more elements that can be separated using physical means such as filtration, evaporation,...etc
A mixture can be one of two types:
1- homogeneous mixture where you cannot identify the elements easily by the naked eye. Example is sugar and water mixture.
2- heterogeneous mixture where you can easily identify the elements through naled eye.
Example is mixture of rocks and sand.
Based on the above, you can easily infer that:
a heterogeneous mixture is a mixture in which the components retain their identity.
Answer:
B. 0.16 m
Explanation:
The vertical distance by which the player will miss the target is equal to the vertical distance covered by the dart during its motion.
Since the dart is thrown horizontally, the initial vertical velocity is zero:
![v_y = 0](https://tex.z-dn.net/?f=v_y%20%3D%200)
While the horizontal velocity is
![v_x = 15 m/s](https://tex.z-dn.net/?f=v_x%20%3D%2015%20m%2Fs)
The horizontal distance covered is
![d_x = 2.7 m](https://tex.z-dn.net/?f=d_x%20%3D%202.7%20m)
Since the dart moves by uniform motion along the horizontal direction, the time it takes for covering this distance is
![t=\frac{d_x}{v_x}=\frac{2.7 m}{15 m/s}=0.18 s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd_x%7D%7Bv_x%7D%3D%5Cfrac%7B2.7%20m%7D%7B15%20m%2Fs%7D%3D0.18%20s)
along the vertical direction, the motion is a uniformly accelerated motion with constant downward acceleration g=9.8 m/s^2, so the vertical distance covered is given by
![d_y = \frac{1}{2}gt^2=\frac{1}{2}(9.8 m/s^)(0.18 s)^2=0.16 m](https://tex.z-dn.net/?f=d_y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2%3D%5Cfrac%7B1%7D%7B2%7D%289.8%20m%2Fs%5E%29%280.18%20s%29%5E2%3D0.16%20m)