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yawa3891 [41]
3 years ago
7

And object which is 3cm high is placed vertically 10cm in front of a concave mirror. If this object produces an image 40cm from

the mirror, the height of the image is ?​
Physics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

25cm is the answer I think

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Is an ocean wave electromagnetic or mechanical
swat32

Answer:

mechanical

Explanation:

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2. A solid plastic cube of side 0.2 m is submerged in a liquid of density 0.8 hgm calculate the
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Answer:

vpg = 0.064 N

Explanation:

Upthrust = Volume of fluid displaced

upthrust liquid on the cube g=10ms−2

vpg =0.2 x 0.2 x 0.2 x0.8 x 10= 0.064N

vpg = 0.064 N

hope it helps.

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I need help someone help me
GaryK [48]

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To develop muscle tone, a woman lifts a 2.50 kg weight held in her hand. She uses her biceps muscle to flex the lower arm throug
Romashka [77]

To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:

\tau = Fr

Where,

F = Force

r = Radius

Replacing we have that,

\tau = Fr

\tau = 21cm (\frac{1m}{100cm})* 550N

\tau = 11.55Nm

The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore

I = 0.25Kg\cdot m^2 +(2.5kg)(0.24m)^2

I = 0.394kg\cdot m^2

Finally, angular acceleration is a result of the expression of torque by inertia, therefore

\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}

\alpha = \frac{11.55}{0.394}

\alpha = 29.3 rad/s^2

PART B)

The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians (\pi / 3), therefore

W = \tau \theta

W = 11.5* \frac{\pi}{3}

W = 12.09J

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3 years ago
You slide a hockey puck across the ice in a hockey rink
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Answer-

mk thats kool.

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3 years ago
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