What net force is required to keep a 500 kg object moving with a constant velocity of 10 m/s?
1 answer:
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Answer:
t = 3.48 s
Explanation:
The time for the maximum height can be calculated by taking the derivative of height function with respect to time and making it equal to zero:
where,
v₀ = initial speed = 110 ft/s
Therefore,
<u>t = 3.48 s</u>
Answer: It states that the BCD equivalent would be 0001000100000000000100010001000100010000000100000001000000000001.
