Answer: a) 0.06 M
b) 3.13 grams.
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
![Molarity=\frac{moles}{\text {Volume in L}}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7Bmoles%7D%7B%5Ctext%20%7BVolume%20in%20L%7D%7D)
Moles of ![Cl^-=Molarity\times {\text {Volume in L}}=0.240\times 0.2L=0.048moles](https://tex.z-dn.net/?f=Cl%5E-%3DMolarity%5Ctimes%20%7B%5Ctext%20%7BVolume%20in%20L%7D%7D%3D0.240%5Ctimes%200.2L%3D0.048moles)
The balanced reaction for dissociation will be:
![SnCl_4\rightarrow Sn^{4+}+4Cl^{-}](https://tex.z-dn.net/?f=SnCl_4%5Crightarrow%20Sn%5E%7B4%2B%7D%2B4Cl%5E%7B-%7D)
Thus for 4 moles of
, there is 1 mole of ![SnCl_4](https://tex.z-dn.net/?f=SnCl_4)
Thus moles of ![SnCl_4=\frac{1}{4}\times 0.048=0.012](https://tex.z-dn.net/?f=SnCl_4%3D%5Cfrac%7B1%7D%7B4%7D%5Ctimes%200.048%3D0.012)
Molarity of ![SnCl_4=\frac{moles}{\text {Volume in L}}=\frac{0.012}{0.2L}=0.06M](https://tex.z-dn.net/?f=SnCl_4%3D%5Cfrac%7Bmoles%7D%7B%5Ctext%20%7BVolume%20in%20L%7D%7D%3D%5Cfrac%7B0.012%7D%7B0.2L%7D%3D0.06M)
Thus the molarity of the
solution = 0.06 M
b) Mass of
= ![moles\times {\text {Molar mass}}=0.012mol\times 260.522g/mol=3.13g](https://tex.z-dn.net/?f=moles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D0.012mol%5Ctimes%20260.522g%2Fmol%3D3.13g)
Thus mass of
Wenzhou use is 3.13 grams.
The mass of
required will be 0.6075 g.
Calculation of mass:
The reaction:
![Na_2CrO_4 + 2AgNO_3 \rightarrow Ag_2CrO_4 + 2NaNO_3](https://tex.z-dn.net/?f=Na_2CrO_4%20%2B%202AgNO_3%20%5Crightarrow%20Ag_2CrO_4%20%2B%202NaNO_3)
Volume of
= 75 mL
Concentration of
= 0.100 M
Step 1:
Molarity is moles of solute in 1000 mL of the solution.
![M=\frac{n}{V}\times 1000\\\\ n=\frac{M\times V}{1000} \\\\n=\frac{0.100\times 75}{1000}\\\\n= 0.0075](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bn%7D%7BV%7D%5Ctimes%201000%5C%5C%5C%5C%20n%3D%5Cfrac%7BM%5Ctimes%20V%7D%7B1000%7D%20%5C%5C%5C%5Cn%3D%5Cfrac%7B0.100%5Ctimes%2075%7D%7B1000%7D%5C%5C%5C%5Cn%3D%200.0075)
Moles of
= 0.0075
Step 2:
From the above equation,
2 moles of
is precipitated by 1 mole of ![Na_2CrO_4](https://tex.z-dn.net/?f=Na_2CrO_4)
So, 0.0075 moles will be precipitated by-
moles of ![Na_2CrO_4](https://tex.z-dn.net/?f=Na_2CrO_4)
= 0.00375 moles of ![Na_2CrO_4](https://tex.z-dn.net/?f=Na_2CrO_4)
Step 3:
![mole=\frac{Given \,weight}{Molar\, mass} \\](https://tex.z-dn.net/?f=mole%3D%5Cfrac%7BGiven%20%5C%2Cweight%7D%7BMolar%5C%2C%20mass%7D%20%5C%5C)
Molar mass of
= 162 g/mol
![0.00375=\frac{x}{162} \\x= 0.00375\times 162\\x= 0.6075 g](https://tex.z-dn.net/?f=0.00375%3D%5Cfrac%7Bx%7D%7B162%7D%20%5C%5Cx%3D%200.00375%5Ctimes%20162%5C%5Cx%3D%200.6075%20g)
So, Mass of
required will be 0.6075 g.
Learn more about Dilution factor here:
brainly.com/question/2186408
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Answer:
c
Explanation:
there are billions of cells in living things. We are made out of millions of cells
Answer:
Lets Write Down the Given Initial Conditions.
![P_2 = --](https://tex.z-dn.net/?f=P_2%20%3D%20--)
![V_2 = 47.6ml](https://tex.z-dn.net/?f=V_2%20%3D%2047.6ml%20)
![T_2 = 77](https://tex.z-dn.net/?f=T_2%20%3D%2077)
In Order to Solve for the Unknown: ![P_2](https://tex.z-dn.net/?f=P_2)
we must use the Ideal Gas Law to Solve for the Second Unknown pressure:
![\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%20%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
Then Rearrange this equation in a form where P2 can be solved from:
![P_2 = \frac{P_1V_1T_2}{T_1V_2}](https://tex.z-dn.net/?f=P_2%20%3D%20%5Cfrac%7BP_1V_1T_2%7D%7BT_1V_2%7D)
Then Insert the Values from above to solve:
![P_2 = \frac{(751 mmHg)(63.2ml)(77C)}{(47.6ml)(42C)}](https://tex.z-dn.net/?f=P_2%20%3D%20%5Cfrac%7B%28751%20mmHg%29%2863.2ml%29%2877C%29%7D%7B%2847.6ml%29%2842C%29%7D)
The Answer is : 1830 mmHg considering sig figs
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