Answer:
When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral.
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The five strategies could include; 1) research the question of clean water availability on line and in books (2 strategies), 2) interview or ask those affected by lack of availability of clean water and find out how it affects them 3) consult with other groups ie political groups also concerned with this question and find out what they did to ensure availability to clean water and lastly to take actions to fight for the accessibility of clean water for certain groups of people like the First Nations people on reserves in Canada.
Answer:
Explanation:
given reaction
2O₃ ⇄ 3O₂
initial 1 1
final 1-x 1+ 1.5x
rate of reaction = k [ O₃ ]² / [ O₂ ]
initial rate = k . 1² / 1 = k
final rate = k (1-x )² / (1+ 1.5x) = k/2
(1-x )² / (1+ 1.5x) = 1/2
2x² - 5.5 x + 1 = 0
x = 0.196
So fraction of ozone reacted = .196
Answer:
2
Step-by-step explanation:
A. Moles before mixing
<em>Beaker I:
</em>
Moles of H⁺ = 0.100 L × 0.03 mol/1 L
= 3 × 10⁻³ mol
<em>Beaker II:
</em>
Beaker II is basic, because [H⁺] < 10⁻⁷ mol·L⁻¹.
H⁺][OH⁻] = 1 × 10⁻¹⁴ Divide each side by [H⁺]
[OH⁻] = (1 × 10⁻¹⁴)/[H⁺]
[OH⁻] = (1 × 10⁻¹⁴)/(1 × 10⁻¹²)
[OH⁻] = 0.01 mol·L⁻¹
Moles of OH⁻ = 0.100 L × 0.01 mol/1 L
= 1 × 10⁻³ mol
B. Moles after mixing
H⁺ + OH⁻ ⟶ H₂O
I/mol: 3 × 10⁻³ 1 × 10⁻³
C/mol: -1 × 10⁻³ -1 × 10⁻³
E/mol: 2 × 10⁻³ 0
You have more moles of acid than base, so the base will be completely neutralized when you mix the solutions.
You will end up with 2 × 10⁻³ mol of H⁺ in 200 mL of solution.
C. pH
[H⁺] = (2 × 10⁻³ mol)/(0.200 L)
= 1 × 10⁻² mol·L⁻¹
pH = -log[H⁺
]
= -log(1 × 10⁻²)
= 2
The chemical name is ferric oxide or iron (III) oxide or hematite. We can found it naturaly as a magnetite, mineral.
