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Marat540 [252]
2 years ago
7

The section 5(a)(1) of the osh act is commonly known as

Engineering
2 answers:
Allisa [31]2 years ago
4 0

Answer:

the General Duty Clause

Commonly known as the General Duty Clause, Section 5(a)(1) of the Occupational Safety and Health Act of 1970 is intended to give OSHA a means to address hazards for which no standard is on the books. Current examples include heat-related illnesses and workplace violence in health care and social services.

Explanation:

lianna [129]2 years ago
4 0

Answer:

as?

Explanation:

have a nice dayy good morning^^

You might be interested in
A brass alloy is known to have a yield strength of 275 MPa (40,000 psi), a tensile strength of 380 MPa (55,000 psi), and an elas
zlopas [31]

Answer:

The magnitude of the load can be computed  because it is mandatory in order to produce the change in length ( elongation )

Explanation:

Yield strength = 275 Mpa

Tensile strength = 380 Mpa

elastic modulus = 103 GPa

The magnitude of the load can be computed  because it is mandatory in order to produce the change in length ( elongation ) .

Given that the yield strength, elastic modulus and strain that is experienced by the test spectrum are given

strain = yield strength / elastic modulus

          = 0.0027

3 0
3 years ago
Before turning in a test, it would be best to
Doss [256]

Answer:

check the grammar and double check the work.Explanation:

sorry if its wrong :P

4 0
3 years ago
Read 2 more answers
Determine the resistance of 3km of copper having a diameter of 0,65mm if the resistivity of copper is 1,7x10^8
LUCKY_DIMON [66]

Answer:

Resistance of copper = 1.54 * 10^18 Ohms

Explanation:

<u>Given the following data;</u>

Length of copper, L = 3 kilometers to meters = 3 * 1000 = 3000 m

Resistivity, P = 1.7 * 10^8 Ωm

Diameter = 0.65 millimeters to meters = 0.65/1000 = 0.00065 m

Radius, r = \frac {diameter}{2}

Radius = \frac {0.00065}{2}

Radius = 0.000325 m

To find the resistance;

Mathematically, resistance is given by the formula;

Resistance = P \frac {L}{A}

Where;

  • P is the resistivity of the material.
  • L is the length of the material.
  • A is the cross-sectional area of the material.

First of all, we would find the cross-sectional area of copper.

Area of circle = πr²

Substituting into the equation, we have;

Area  = 3.142 * (0.000325)²

Area = 3.142 * 1.05625 × 10^-7

Area = 3.32 × 10^-7 m²

Now, to find the resistance of copper;

Resistance = 1.7 * 10^{8} \frac {3000}{3.32 * 10^{-7}}

Resistance = 1.7 * 10^{8} * 903614.46

<em>Resistance = 1.54 * 10^18 Ohms </em>

3 0
3 years ago
Which of the following components allows a vehicle's drive wheels to revolve at different speeds while cornering? A. Clutch B. T
nalin [4]

Answer:

C.Differential

Explanation:

While vehicle is moving in a curve track there there is a difference between the speed of inner and outer wheel of vehicle.The inner wheels  move slowly while outer wheels  move faster as compare two inner wheels.Because outer wheels have to cover more distance as compare to inner wheels in the sane time limit.

All above process is carried by using a differential .Differential is a speed changer unit and comes under the picture when vehicle is moving in a curve path.

6 0
3 years ago
A 1 250 kg car moving at a velocity of 30 km/hr along EDSA is accelerated by a force of 1 700 N. What will be its velocity after
Talja [164]
<h3><u>The velocity of the car after 10 s is 78.95 km/hr</u></h3>

Explanation:

<h2>Given:</h2>

m = 1,250 kg

v_i = 30 km/hr

F = 1,700 N

t = 10 s

<h2>Required:</h2>

Final velocity

<h2>Equation:</h2><h3>Force</h3>

F = ma

where: F - force

m - mass

a - acceleration

<h3>Acceleration</h3>

a = \frac{v_f \:-\:v_i}{t}

where: a - acceleration

v_i - initial velocity

v_f - final velocity

t - time elapsed

<h2>Solution:</h2><h3>Solve for acceleration using the formula for force</h3>

F = ma

Substitute the value of F and m

(1700 N) = (1250 kg)(a)

a = \frac{1700\:N}{1250\:N}

a = 1.36 m/s²

<h3>Solve for final velocity using the formula for acceleration</h3>
  • Convert 30 km/hr to m/s

= \frac{30\:km}{hr}\:×\:\frac{1000\:m}{1\:m}\:×\:\frac{1\:hr}{3600\:s}

= 8.33 m/s

  • Substitute the value of a, v_i and t

a = \frac{v_f \:-\:v_i}{t}

1.36\: m/s² \:= \:\frac{v_f \:-\:8.33\:m/s}{10\:s}

(10 \:s)1.36\: m/s² \:= \:v_f \:-\:8.33\:m/s

v_f\: =\: (10 \:s)1.36 \:m/s²\: + \:8.33\:m/s

v_f \: =\: 13.6 \:m/s \:+\: 8.33\:m/s

v_f\: =\:  21.93\: m/s

  • Convert to km/hr

= \frac{21.93\:m}{s}\:×\:\frac{1\:km}{1000\:m}\:×\:\frac{3600\:s}{1/:hr}

= 78.95\: km/hr

<h2>Final answer</h2><h3><u>The velocity of the car after 10 s is 78.95 km/hr</u></h3>
6 0
3 years ago
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