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Naddika [18.5K]
3 years ago
8

Hat coefficients are needed to balance the equation for the complete combustion of methane? enter the coefficients in the order

ch4, o2, co2, and h2o, respectively.
Chemistry
1 answer:
klio [65]3 years ago
7 0
The chemical equation for the combustion of methane is CH4 + 2O2 --> CO2 + 2H2O.

The coefficients of that equation are 1, 2, 1, and 2, in the order you asked for.
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What is the mass in 0.25 mol of SO2
gulaghasi [49]

0.25 mols SO₂ x 64.058 g SO₂/ 1 mol SO₂ = 16.0145 g SO₂

molar mass of SO₂: 64.058 g

answer: 16 grams of SO₂ (2 sig figs)

check the question to see if its asked for a specific unit for mass (grams or kilograms, if they asked for kiligrams then convert 16 grams to kilograms by dividing it by 1000)


5 0
3 years ago
How do you find the volume of a liquid
mart [117]
Today they will practice measuring different liquids. They will use a container called a graduated cylinder to measure liquids. Graduated cylinders have numbers on the side that help you determine the volume. Volume is measured in units called liters or fractions of liters called milliliters (ml).
7 0
3 years ago
Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equat
Evgesh-ka [11]

Answer:

30 cm³

Explanation:

Step 1: Given data

  • Density of aluminum (ρ): 2.7 g/cm³
  • Mass of aluminum (m): 81 g
  • Volume occupied by aluminum (V): ?

Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

4 0
3 years ago
What does an object's apparent size depend on?
ipn [44]

Answer:

D. its actual size and distance from an observer

Explanation:

haha aint i the brainliest

jst kidding

hope it helped u

3 0
3 years ago
A hydrate of CoCl2 has a mass of 17.40 g before heating. After heating, the mass of the anhydrous compound is found to be 10.27
melisa1 [442]

Mass CoCl2 = 10.27 g
moles CoCl2 = 10.27 g/ 129.839 g/mol=0.07910

mass water = 17.40 - 10.27=7.13 g
moles water = 7.13 / 18.02 g/mol=0.396

0.396/ 0.07910=5

CoCl2 * 5 H2O

moles CaF2 = 85.8 g/ 78.0748 g/mol=1.10
moles Ca = 1.10
mass Ca = 1.10 x 40.078 g/mol=44.1 g
V = 44.1 / 1.55 =28.5 mL

Greetings!!
5 0
3 years ago
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