Answer : The volume of carbon dioxide will be, 5.6122 L
Solution : Given,
Moles of LiOH = 0.5 moles
Molar mass of carbon dioxide = 44 g/mole
Density of carbon dioxide = 0.00196 g/ml
First we have to calculate the mass of carbon dioxide.
The balanced reaction will be,
![2LiOH+CO_2\rightarrow Li_2CO_3+H_2O](https://tex.z-dn.net/?f=2LiOH%2BCO_2%5Crightarrow%20Li_2CO_3%2BH_2O)
From the reaction we conclude that
As, 2 moles of LiOH absorbs 44 grams of carbon dioxide
So, 0.5 moles of LiOH absorbs
grams of carbon dioxide
Mass of carbon dioxide = 11 g
Density of carbon dioxide = 0.00196 g/ml
Now we have to calculate the volume of carbon dioxide.
![Density=\frac{Mass}{volume}](https://tex.z-dn.net/?f=Density%3D%5Cfrac%7BMass%7D%7Bvolume%7D)
![0.00196g/ml=\frac{11g}{volume}](https://tex.z-dn.net/?f=0.00196g%2Fml%3D%5Cfrac%7B11g%7D%7Bvolume%7D)
Volume of carbon dioxide = 5612.24 ml = 5.6122 L (1 L = 1000 ml)
Therefore, the volume of carbon dioxide will be, 5.6122 L