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zalisa [80]
2 years ago
11

Suppose you want to make the demonstration more dramatic by attracting as much hair as possible with the balloon. Which of the f

ollowing is the best choice to accomplish your goal? A. Decrease the electric force by holding the balloon closer to the hair. B. Increase the electric force by rubbing the balloon for a longer period of time. C. Decrease the electric force by using a larger balloon. D. Increase the electric force by holding the balloon farther away from the hair.
Physics
1 answer:
Artist 52 [7]2 years ago
6 0

Answer:

B. Increase the electric force by rubbing the balloon for a longer period of time.

Explanation:

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A student walks 350 m [S], then 400 m [E20°N], and finally 550 m [N10°W]. Using the component method, find the resultant (total)
levacccp [35]

In component form, the displacement vectors become

• 350 m [S]   ==>   (0, -350) m

• 400 m [E 20° N]   ==>   (400 cos(20°), 400 sin(20°)) m

(which I interpret to mean 20° north of east]

• 550 m [N 10° W]   ==>   (550 cos(100°), 550 sin(100°)) m

Then the student's total displacement is the sum of these:

(0 + 400 cos(20°) + 550 cos(100°), -350 + 400 sin(20°) + 550 sin(100°)) m

≈ (280.371, 328.452) m

which leaves the student a distance of about 431.8 m from their starting point in a direction of around arctan(328.452/280.371) ≈ 50° from the horizontal, i.e. approximately 431.8 m [E 50° N].

5 0
2 years ago
6. A 2000 kg spacecraft is located 9.2x10 m from the center of the earth. The mass of the earth
Zina [86]

The answer is -i, trust me.

3 0
2 years ago
The sound level of one person talking at a certain distance from you is 61 dB. If she is joined by 5 more friends, and all of th
Lady_Fox [76]

Answer:

Explanation:

For sound level in decibel scale the relation is

dB = 10 log I / I₀ where I₀ = 10⁻¹² and I is intensity of sound whose decibel scale is to be calculated .

Putting the given values

61 = 10 log I / 10⁻¹²

log I / 10⁻¹² = 6.1

I = 10⁻¹² x 10⁶°¹

=10^{-5.9}

intensity of sound of 5 persons

I=5\times 10^{-5.9}

dB=10log\frac{5 X 10^{-5.9}}{10^{-12}}

= 10log 5 x 10⁶°¹

= 10( 6.1 + log 5 )

= 67.98

sound level will be 67.98 dB .

4 0
3 years ago
one car accelerates at half the rate of another how much longer does it take the first car to travel a quarter mile
Orlov [11]

Answer:

t=1/4v1

Explanation:

Given data

Car one

Speed =v1

Time =t

Distance =1/4 mile

Given data

Car two

Speed =v1/2

Time =t

Distance =d

Speed =distance/time

v1=1/4/t

v1t=1/4

t=1/4*1/v1

t=1/4v1 seconds

7 0
2 years ago
6x10^8 kg<br> —————<br> 2x10^4 m^3
barxatty [35]
The answer to the question

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3 years ago
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