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2 years ago

A stainless steel knife has a mass of 849 grams. It has a density of 7.86 g/cm³. What is the volume of the knife?

Chemistry

1 answer:

Tcecarenko [31]2 years ago

4 0

Answer:

108.02cm³

Explanation:

First, rearrange the formula: density = mass/volume so that volume is the subject: volume = mass/density

Next, substitute (plug in) the values:

volume = 849 ÷ 7.86 = 108.01526... ≈ 108.02cm³

The volume of the knife is 108.02cm³

Hope this helps!

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A chemist wants to find Kc for the following reaction at 709 K:2NH3(g) + 3 I2 (g) ----> 6HI(g) + N2(g)

irakobra [83]

Answer:

422455.41

Explanation:

Corrected from source,

Given that:-

$N2(g) + 3 H2(g)\rightarrow 2NH3(g) \ Kc_1 = 0.314$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant the reaction

$2NH3(g)\rightarrow N2(g) + 3 H2(g)$

is:

$Kc_{1}'=\frac{1}{0.314}$

$H2(g) + I2(g)\rightarrow 2 HI(g)\ Kc_2 = 51$

If the equation is multiplied by a factor of '3', the equilibrium constant of the reverse reaction will be the cube of the equilibrium constant of initial reaction.

The value of equilibrium constant the reaction

$3H2(g) + 3I2(g)\rightarrow 6 HI(g)$

is:

$Kc_{2}'={51}^3$

Adding both the reactions we get the final reaction. So, the equilibrium constants must be multiplied.

The value of equilibrium constant the reaction

$2NH3(g) + 3I2(g)\rightarrow 6 HI(g) + N2(g)$

is:

$Kc'=\frac{1}{0.314}\times {51}^3$ = 422455.41

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3 years ago

How are real gases different from ideal gases?

Anettt [7]

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2 years ago

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maria [59]

Answer:

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