A car move at an initial velocity of 240m and reach at the final velocity of 540m in 8hours. calculate its acceleration.
1 answer:
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Answer:
α = 0.0135 rad/s²
Explanation:
given,
t = 133 min = 133 x 60 = 7980 s
angular speed varies from 570 rpm to 1600 rpm
now,
570 rpm =
= 59.69 rad/s
1600 rpm = =
= 167.6 rad/s
using equation of rotational motion
ωf = ωi + αt
167.6 = 59.7 + α x 7980
α x 7980 = 107.9
α = 0.0135 rad/s²
0 = u^2 + 2*(-2)*9600
u^2 = 38400
u = 195.96 m/s